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3 years ago

One side of a regular hexagon is 9 units.What is the perimeter of the hexagon?

Mathematics

1 answer:

schepotkina [342]3 years ago

5 0

It is 54 because you have to do 9 multipied by 6 because a hexagon has 6 sides therefore it is 54

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Ahmed wrote two numbers. The first number has a 7 in its tenth place. The second number has a 7 with a value that’s is 1,000 tim

joja [24]

Answer:

in the thousands place

Step-by-step explanation:

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3 years ago

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What quadratic equation could be solved to find any solutions to the system of equations?

Kipish [7]

Answer:

Step-by-step explanation:

x²+7x-11=-5x+6

x²+7x+5x-11-6=0

x²+12x-17=0

$x=\frac{-12\pm \sqrt{12^2-4*1*(-17)} }{2*1} \\=\frac{-12 \pm \sqrt{144+68} }{2} \\=\frac{-12 \pm \sqrt{212}}{2} \\=\frac{-12+2\sqrt{53}}{2}\\=-6 \pm \sqrt{53}$

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3 years ago

Find the surface area and the volume of the prism .

sdas [7]

Answer:

$14 + 4 + 5.5 + 3 + 5.5 {?}^{2}$

3 0

2 years ago

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AB:BD = 3:4 <br><br> AC:CD = 3:2 <br><br> Work out AB:BC:CD

Papessa [141]

Answer:

15:6:14

Step-by-step explanation:

AB:BD is split into a total of 3+4=7 parts.

AC:CD is split into a total of 3+2=5 parts.

So, if the two ratios are put on a number line together with the points A, B, C, and D, the number line would be split into a total of 35 parts (the LCM of 7 and 5).

AB would be (3/7)*35=15.

CD would be (2/5)*35=14

BC would be 35-(15+14)=6

So, the ratio is 15:6:14.

5 0

3 years ago

a) How many social security cards can be issued with no repeated digits? b) How many social security cards that can be issued wi

ad-work [718]

Answer:

a) How many social security cards can be issued with no repeated digits?

We have 10 numbers from 0 to 9. When no digit is repeated, so we get 10! ways that is = $10\times9\times8\times7\times6\times5\times4\times3\times2\times1$

= 3628800

b) How many social security cards that can be issued with at least one digit repeated?

We will get this by subtracting 10! from all possible cases.

$10^{9}-10!$

= $1000000000-3628800=996371200$

Exercise 4.

a) How many nonempty subsets are in a set of 5 elements?

Each element has 2 choices that are either selected in subset or not selected in subset.

Here, total choices will be $2^{5}$

And it is 1 time that no element is selected.

So, the number of non empty subsets will be = $2^{5}-1$

=> $32-1=31$

b) Erika has 5 friends. In how many ways can she invite one or more friends to a dinner party?

Same like above part, here Erika has two choices for each friend, either invite or not invite.

So, she has total $2^{5}=32$ choices.

1 way to not invite anyone.

Hence, the number of ways can she invite one or more friends to a dinner party = $32-1=31$ ways.

8 0

3 years ago