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SCORPION-xisa [38]
4 years ago
6

Create an original rational function that has at least one asymptote (vertical, horizontal, and/or slant) and possibly a removab

le discontinuity. List these features of your function: asymptote(s) (vertical, horizontal, slant), removable discontinuity(ies), x-intercept(s), y-intercept, and end behavior.
Thank you in advance :)
Mathematics
1 answer:
harkovskaia [24]4 years ago
8 0
Since f has a vertical at x=2, then the denominator of the rational function contains the term (x-2), Function f has the form. F(x)=g(x) / (x-2) g(x) which is in the numerator must be of the same degree as the denominator since F has a horizontal asymptote. Also g (x) must contain the term (x+5) since f has a zero at x=-5. Hence f(x)=3 (x+5) / (x-2)
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Determine how (if possible) the triangles can be proved similar.
HACTEHA [7]

Answer:

opposite sides are congruent and parrallel

Step-by-step explanation:

im pretty sure im correct because i learned this in 10th grade for Algebra

7 0
3 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
Is 25 60 65 a right triangle
Sauron [17]

Answer:

No

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
What is the y intercept of the line given by the equation below? y=4x-3
Daniel [21]

Answer:

y-intercept of y=4x-3 is -3

Step-by-step explanation:

The given equation is:

y = 4x -3

The equation is in slope-intercept form.

The standard equation of slope-intercept form is:

y = mx + b

where m is the slope and b is the y-intercept

So, comparing the given equation with the standard equation the y-intercept is -3

y-intercept of y=4x-3 is -3

3 0
3 years ago
Read 2 more answers
Find the volume of the cylinder in terms of π.
ValentinkaMS [17]

Hello There!

The volume for a cylinder is Pi*r^2*h

We are going to leave our Answer in terms of pi so first we need to square our radius which we know is 5

Our radius is 25 because we squared 5. Next, we need to multiply 25 by our height which is 11.

25 multiplied by 11 is 275 so our Answer would be 275\pi

6 0
4 years ago
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