Can you rewrite the equation? It doesn’t make sense
Answer:
The truck travel must to have a constant speed of ![22.06\ ft/sec](https://tex.z-dn.net/?f=22.06%5C%20ft%2Fsec)
Step-by-step explanation:
we have
![d=1.3t^{2}+t+2](https://tex.z-dn.net/?f=d%3D1.3t%5E%7B2%7D%2Bt%2B2)
where
d expresses a car's distance in feet
t is the number of seconds
<em>Find the distance d for t=8 sec</em>
![d=1.3(8)^{2}+8+2=93.2\ ft](https://tex.z-dn.net/?f=d%3D1.3%288%29%5E%7B2%7D%2B8%2B2%3D93.2%5C%20ft)
<em>Find the distance d for t=8.2 sec</em>
![d=1.3(8.2)^{2}+8.2+2=97.612\ ft](https://tex.z-dn.net/?f=d%3D1.3%288.2%29%5E%7B2%7D%2B8.2%2B2%3D97.612%5C%20ft)
The total distance in this interval of 0.2 sec is
![97.612-93.2=4.412\ ft](https://tex.z-dn.net/?f=97.612-93.2%3D4.412%5C%20ft)
<em>Find the speed of the car</em>
Divide the total distance by the time
![4.412/0.2=22.06\ ft/sec](https://tex.z-dn.net/?f=4.412%2F0.2%3D22.06%5C%20ft%2Fsec)
therefore
The truck travel must to have a constant speed of ![22.06\ ft/sec](https://tex.z-dn.net/?f=22.06%5C%20ft%2Fsec)
Answer:
20 is correct answer
Step-by-step explanation:
8+3×4
=8+12
=20
<em>Reme</em><em>mber</em><em> </em><em>always</em><em> </em><em>foll</em><em>ow</em><em> </em><em>bodmas</em><em> </em><em>rule</em><em> </em>
hope it helped you:)
thanks!
Well you will say 17.8÷3.9=17.8×10÷3.9×10=178÷39=4.56410256410256 rounded to the nearest hundreds is 4.56.
Answer:
i dont know
Step-by-step explanation: