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1 year ago

Explain why 8 < x < 2 has no solution? need the answer quick

Mathematics

1 answer:

lord [1]1 year ago

8 0

Answer:

8 < x < 2 has no solution because there is no number greater than 8 (8 < x), yet less than 2 (x < 2). It's impossible, so there is no solution.

If the inequality was something like 8 < x < 10, then it will work because 8 can be less than x and x can be less than 10.

Hope this helps and have a great rest of your day! :)

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If integral 1 to 5 f(x)dx =36/15 what is the value of integral from 5 to 1 f(x)dx?

fredd [130]

Answer:

-36/15

Step-by-step explanation:

If the indefinite integral of f(x)dx is F(x), then your integral from 1 to 5 is ...

F(5) -F(1) = 36/15

The integral in the reverse direction is ...

F(1) -F(5) = -(F(5) -F(1)) = -36/15

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Tom wants to buy 10 shirts.

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Answer:

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Step-by-step explanation:

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2 years ago

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Find the probability of rolling two number cubes and getting a 2 on the first number cube and a 6 on the second?

Tanzania [10]

Answer:

Step-by-step explanation:

A cube has 6 sides

Only one side of the cube has 2 on it

The probability of getting 2 would be 1/6

Only one side of the cube has 6 on it

The probability of getting 6 would be 1/6

For both events to happen together

1/6 x 1/6 = 1/36

4 0

3 years ago

An employee’s salary for Alar Services is $37,500. Next year, she will get an 8% increase in salary. How much is her new salary?

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40500 is the answer
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2 years ago

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Solve the equation : <img src="https://tex.z-dn.net/?f=%20%5Ccos%28x%29%20-%20%20%5Csin%28x%29%20%20%3D%20%20%5Csqrt%7B2%20%

Debora [2.8K]

Answer:

General solution is

$x = n \pi + \frac{\pi }{8}$

Step-by-step explanation:

Step(i):-

Given cos x - sin x = √2 cos (3 x)

Dividing '√2' on both sides , we get

$\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }$

we will use trigonometry formulas

a) Cos ( A + B) = Cos A Cos B - sin A sin B

b) $cos \frac{\pi }{4} = \frac{1}{\sqrt{2} }$

Step(ii):-

$\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }$

$cos (\frac{\pi }{4} ) cos x - sin(\frac{\pi }{4} ) sin x = cos 3x$

$cos (\frac{\pi }{4}+x ) = cos 3 x$

Step(iii):-

General solution of cos x = cos ∝ is x = 2 nπ+∝

we have $cos (\frac{\pi }{4}+x ) = cos 3 x$

The general solution of $cos (\frac{\pi }{4}+x ) = cos 3 x$ is

⇒ $3 x = 2 n \pi + (\frac{\pi }{4}+x )$

⇒ $3 x- x = 2 n \pi + \frac{\pi }{4}$

$2x = 2 n \pi + \frac{\pi }{4}$

final answer:-

General solution is

$x = n \pi + \frac{\pi }{8}$

8 0

2 years ago