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OLga [1]
4 years ago
12

for each of the given elements list two other elements with similar chemical properties iodine, barium, iron

Chemistry
2 answers:
natulia [17]4 years ago
6 0
Copper and leand I think
Travka [436]4 years ago
3 0
Copper and lead. I'm not 100% sure, you might want to check your periodic table.
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How many hydrogen atoms are in 3.90 mol of ammonium sulfide?
lozanna [386]

Answer:

First, the number of ammonium sulfide molecules should be calculated:

N = NA × n,

where NA - the Avogadro number, n - number of moles.

N (ammonium sulfide) = 6.022 × 1023 × 8.5 mol = 51.187 × 1023.

The moelcular formula of ammonium sulfide is (NH4)2S. It means that each molecule contains 8 hydrogen atoms.

As a result, 8.5 mol of (NH4)2S contain:

51.187 × 1023 × 8 = 41 × 1024 hydrogen atoms.

Answer: 41 × 1024 hydrogen atoms

8 0
3 years ago
What is the process of using one or more of your five senses to measure or collect data?
sveta [45]

Answer:

B no observation pls mark me branilest

7 0
3 years ago
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When a negatively charged species is most appropriately depicted as a hybrid of several resonance forms, the negative charge pre
Varvara68 [4.7K]

Answer:

True

Explanation:

Resonance is a concept that was introduced when it was not possible to represent a compound with a single Lewis structure. Lewis formulas represent localized electrons, either shared by two atoms in a covalent bond or as non-shared electrons belonging to a given atom. Certain organic compounds, especially those containing multiple bonds can be described by more than one Lewis structure. In these cases, the true Lewis structure has an electronic distribution that is a "hybrid" of all possible Lewis structures of that molecule. Each of Lewis's structures is known as resonance or canonical forms and they are related to each other by a double-headed arrow, where all possible positions of electrons in that molecule are represented.

This type of compound has multiple bonds (double or triple) where electrons are not fixed, but move quickly between atoms, "resonating" between the different Lewis structures. For this reason, when a resonance hybrid has a negative charge, this charge moves between the different resonant structures.

Many times, an intermediate Lewis structure is drawn, with dotted lines, simulating approaching the real structure of the compound, and where this phenomenon of electron and charge mobility can be observed. For example, as we can observe in the ozone resonance image.

5 0
3 years ago
A vessel contained N2, Ar, He, and Ne. The total pressure in the vessel was 1100 torr. The partial pressures of nitrogen, argon,
geniusboy [140]

Answer:

Partial pressure Ne = 340 Torr

Option B

Explanation:

Gases contained in the vessel:

N₂, Ar, He, Ne

One of Dalton's law for gases determine this:

In a mixture of gases contained in a vessel, total pressure of the system must be the sum of partial pressure of each gas.

Total pressure = 1100 Torr

Let's replace:

Partial pressure N₂ + Partial pressure Ar + Partial pressure He + Partial pressure Ne  =  1100 Torr

Partial pressure Ne = 1100 Torr - Partial pressure N₂ - Partial pressure Ar  -Partial pressure He

Partial pressure Ne = 1100 Torr - 110 Torr - 250 Torr - 400 Torr

Partial pressure Ne = 340 Torr

8 0
3 years ago
A pure sample of a new chemical compound was analyzed and was found to have the following mass percentages: Al 31.5 %; O 56.1 %;
rjkz [21]

Answer:

The answer to your question is empirical formula   Al₃O₉S

Explanation:

Data

Al = 31.5 %

O = 56.1 %

S = 12.4 %

Process

1.- Look for the atomic masses of the elements

Al = 27 g

O = 16

S = 32

2.- Represent the percentages as grams

Al = 31.5 g

O = 56.1 g

S = 12.4 g

3.- Convert these masses to moles

                               27 g of Al ----------------- 1 mol

                               31.5 g ----------------------  x

                                x = 1.17 moles

                               16 g of O ----------------  1 mol

                               56.1 g of O -------------  x

                                  x = 3.5 mol

                               32 g of S ---------------  1 mol

                               12.4 g of S -------------   x

                                x = 0.39 moles

4.- Divide by the lowest number of moles

Al =   1.17 / 0.39  = 3

O =    3.5 / 0.39 = 8.9 ≈ 9

S  =   0.39 / 0.39 = 1

5.- Write the empirical equation

                                Al₃O₉S

4 0
3 years ago
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