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Tanzania [10]
3 years ago
14

Hey guys. whats with the account telling you to download a file. Is it dangerous?

Chemistry
1 answer:
mash [69]3 years ago
5 0
Probably not but I wouldn’t risk it
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What is the nuclear binding energy of an atom that has a mass defect of 5.0446
notsponge [240]

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
4 years ago
Read 2 more answers
Camphor (C10H16O) melts at 179.8°C, and it has a particularly large freezing-point-depression constant, Kf= 40.0ºC/m. When 0.186
Usimov [2.4K]

Answer:

Molar mass for the unknown solute is 109 g/mol

Explanation:

Freezing point depression is the colligative property that must be applied to solve the question.

T°F pure solvent - T°F solution = Kf . m

Let's analyse the data given

Camphor → solvent

Unknown solute → The mass we used is 0.186g

T°F pure solvent = 179.8°C and T°F solution = 176.7°C.

These data help us to determine the ΔT → 179.8°C - 176.7°C = 3.1°C

So we can replace → 3.1°C  = 40°C/m . m

m = 3.1°C / 40 m/°C → 0.0775 mol/kg

We have these moles of solute in 1kg of solvent, but our mass of camphor is 22.01 g (0.02201 kg).

We can determine the moles of solute → molality . kg

0.0775 mol/kg . 0.02201 kg = 1.70×10⁻³ moles

Molar mass → mass (g) / moles → 0.186 g / 1.70×10⁻³ mol = 109 g/mol

3 0
3 years ago
Read 2 more answers
Rock formations are sculpted into shape by two general forces. What are these?
Allisa [31]

Answer:weathering and erosion

Please mark brainlyest

Explanation:

8 0
3 years ago
Read 2 more answers
Balance the Chemical Equation<br> Pb(OH)2 + HCl ---&gt; H2O + PbCl2<br><br> Please help
Sloan [31]

Answer:

Pb(OH)2 + 2 HCl ---> 2H2o + PbCl2

Explanation:

8 0
3 years ago
2. Calculate the mass of Kool-Aid needed to make 0.1 L solutions at the following concentrations: a. 0.1 M b. 0.2 M c. 0.3 M d.
murzikaleks [220]
477889654 that the mass
4 0
3 years ago
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