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ValentinkaMS [17]
3 years ago
11

B. Find Addition of Binary Numbers: 1100112 + 11012

Computers and Technology
1 answer:
schepotkina [342]3 years ago
7 0
Hello, I assume you mean 110011_2 + 1101_2

To add 110011+ 1101 we can setup the problem like the following:

   110011
+     1101 
-------------
  1000000

When we add 1 + 1 this equals 10 so we just carry the 1 and we keep doing that from right to left. Also 1 + 0 = 1 

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P16 Consider the following network. ISP B provides national backbone service to regional ISP A. ISP C provides national backbone
Art [367]

Solution :

Considering the following data :

$\text{ISP B}$ provides the national backbone to the regional $\text{ISP A}$.

$\text{ISP C}$ provides the national backbone to the regional $\text{ISP D}$.

Each of the ISP consists of one autonomous systems (AS).

$\text{ISP B}$ would like to hand over the traffic of C through the $\text{West}$ Coast.

The $\text{ISP C}$ would like to receive traffic from B's peering point via East Coast.

One way for $C$ to force $B$ to hand over all of $B$’s traffic to $D$ on the east coast is for $C$ to  only advertise its route to $D$ via its east coast peering point with $C$.

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3 years ago
Which statement best describes one reason why assembly language is easier
viktelen [127]

Answer:

machine language uses binary code and assembly language uses mnemonic codes to write a program.

Explanation:

In a nutshell, machine language uses binary code, which is almost impossible for humans to decipher, whereas assembly language uses mnemonic codes to write a program. Mnemonic codes make it simpler for humans to understand or remember something, and so make the language a bit easier for humans to use than machine code.

6 0
2 years ago
How is science and technology related?
garik1379 [7]
Because you use technology to do science
3 0
4 years ago
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What is the most popular airline in the US?
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3 years ago
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Suppose a program is running on a distributed-memory multiprocessor. There are 1,000 instructions in the program and 80% of inst
Licemer1 [7]

Answer:

2125 ns.

Explanation:

First of all Execution Time = Number of Instructions * CPI * Clock Cycle

Number of Instructions = 1000

CPI = 0.5

Clock Cycle = 1/clock rate = 1/4GHz = 0.25 * 10-9 s

So Execution Time = 1000 * 0.5 * 0.25 * 10-9

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So Total Execution Time = 125+2000 = 2125 ns.

5 0
4 years ago
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