Answer:
a . chart area
This describes what is charted. It can be placed above or below the chart.
Explanation:
Answer:
Social networking capabilities could be made available by the presence of SBRUs central servers and local resort's server. For resorts that are using SBRU servers, there will be high bandwidth access to the internet. This can create a service level of 100% availability. However, for the resorts with high usage clients, a local server could be provided. Similar support will be needed and it will encourage local communication. The possible issues will be problems of connectivity, reliability as well as bandwidth.
Explanation:
Social networking capabilities could be made available by the presence of SBRUs central servers and local resort's server. For resorts that are using SBRU servers, there will be high bandwidth access to the internet. This can create a service level of 100% availability. However, for the resorts with high usage clients, a local server could be provided. Similar support will be needed and it will encourage local communication. The possible issues will be problems of connectivity, reliability as well as bandwidth.
Answer:
return tmp;
default:
tmp . token_type = ERROR;
return tmp;
1. In the code, input.GetChar() gets the next character from standard input. If GetToken() is called four times, which of the following inputs will return a token whose type is ERROR?
A. ========
A. =<======
B. ===>====
C. =====<==
D. ======<=
Risk assessment should cover all the processes and systems included in an organization. This means this includes also the technical support including <span>firewalls, secure operating systems and networks, and antivirus protection. Risk is always present and inevitable in every way so it is important to anticipate and make early detections to counter with actions as soon as one can.</span>
Answer:
Probability of getting 3 consecutive tails in a fair coin toss:-
P(E)=0.125
Explanation:
If we toss an unbiased coin exactly three time we can have 8 outputs possible and those outputs are as following:-
- HHH
- HHT
- HTH
- HTT
- THH
- THT
- TTH
- TTT
Out of these 8 outputs we have 1 favorable outcome that is TTT.So the probability of the event is P(E)=1/8
where 8 is total number of outcomes.
