Please refer the photograph for the answer
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Answer:
-i
Step-by-step explanation:
i^0=1
i^1=i
i^2=-1
i^3=-i
i^4=1
This repeats so we want to see how many 4 factors of i there is in i^(23) which is 5 with a remainder of 3.
So i^(23)=i^3=-i.
i^(23)=i^(5*4+3)=(i^4)^5 * (i^3)=(1)^5 * (-i)=1(-i)=-i.
SqR 13/ 2 --> 3.606/2 --> 1.803
Answer:
f(5) = 11
g(3) =13
Step-by-step explanation:
f(5) means put 5 in for x
f(x) = 2x+1
f(5) = 2(5)+1
= 10+1
= 11
g(3) means put 3 in for x
g(x)=2x^2-5
g(3) = 2(3)^2 -5
= 2(9) -5
= 18 -5
=13
What's the radius or the diameter of the cone? The formula is 1/3πr(^2)h <-- r to the power of 2 if that even helps
