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Alexus [3.1K]
3 years ago
5

I got these wrong help needed plz !!

Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0

Answer:  π and √5

<u>Step-by-step explanation:</u>

π is irrational

√5 is irrational

0.3333 is rational (repeating decimal)

√-4 is imaginary (equal to 2i) so is not a Real Number

1/9 is rational (repeating decimal) equal to 0.11111

Lyrx [107]3 years ago
4 0

tiene que sacar la raiz nena

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Plssss I need help Im in classsss plsss
Sav [38]

Step-by-step explanation:

Y=-4x+3

2x+3y=19

2x+3(-4x+3)=19

2x-12x+9=19

-10x=10

X=-1

y=-4*(-1)+3=4+3=7

x=-1 y=7

5 0
3 years ago
PLEASE HELP Complete the table below to find solutions to the linear equation y=5x+35.
Eddi Din [679]

Answer:

x | y | (x,y)

0 | 35 | (0,35)

3 | 50 | (3,50)

-7 | 0 | (-7,0)

Step-by-step explanation:

Given the equation: y = 5x + 35, to complete the table, plug in the value of x given in the table in each row, to find y.

When x = 0,

y = 5(0) + 35

y = 0 + 35

y = 35

(0,35)

When x = 3,

y = 5(3) + 35

y = 15 + 35

y = 50

(3,50)

When x = -7,

y = 5(-7) + 35

y = -35 + 35

y = 0

(-7,0)

6 0
3 years ago
The product of two numbers is 161 , one of number is 7,find the other number. ​
Diano4ka-milaya [45]

let the other number be " n "

now, according to above condition :

  • n × 7 = 161

  • n = 161 ÷ 7

  • n = 23

therefore, the other number would be 23.

4 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
If the slope of one of these parallel lines is 1.25, the slope of the other line is ___.
oksian1 [2.3K]
1.25 also bc they are parallel
6 0
3 years ago
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