6+3n≤40
Use inverse operations i.e.
4x+2<10
-2 -2
4x<8
4*x/4<8/4
x<2
Answer:
s
wd\\\Step-by-step explanation:
Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Answer:
F = $11,421.90
Final value after 5 years F = $11,421.90
Complete question;
You purchased a vehicle for $32,000. It's value will depreciate at a rate of 18.62%. What will it's value be in 5 years, when you finally have it paid off
Step-by-step explanation:
Given;
Initial value P = $32,000
Depreciation rate r = 18.62% = 0.1862
Time t = 5
Final value = F
Using the compound depreciation formula;
F = P(1 - r)^t
Substituting the values;
F = $32,000(1 - 0.1862)^5
F = $11,421.90
Final value F = $11,421.90
Answer:
Given - Twice a no. decrease by 22 is 48
To find - The no.
Solution -
Let the no. be X
According to the question, equation made is -
2x - 22 = 48
2x = 48 + 22
2x = 70
x = 70/2
X= 35
Verification -
35 ×2 - 22 = 48
70 - 22 = 48
48= 48
LHS = RHS
hence proved
