Question

Mrs. Synder must choose two of her homeroom students to be class representatives. The class consists of 13 girls and 9 boys. Approximately what percent chance is there that the first student chosen is a boy and the second student chosen is a girl? (Round to the nearest percent)
A. 10%

B. 25%

C. 22%

D. 15%

Answer 1

9/22 x 13/21 = 0.25 = 25% B

Answer 2

Answer:   B. 25%

Step-by-step explanation:

Given : Number of boys in the class = 13

Number of girls in the class = 9

Total students  = 13+9=22

Now, the number of ways to choose first boy then a girl =$13\times9=117$     (1)

Number of ways to choose nay two students :-

${22}P_{2}=\dfrac{22!}{(22-2)!}\\\\=\dfrac{22\times21\times20!}{20!}=462$     (2)

Now, the probability that the first student chosen is a boy and the second student chosen is a girl :-

$\dfrac{117}{462}=0.253246753247\approx0.25$   [Divide (1) by (2)]

In percent , $0.25\times100=25\%$

Hence, approximately 25% chance that the first student chosen is a boy and the second student chosen is a girl.