Answer:
Step-by-step explanation:
1 pound = 16 ounce
6 pound = 6 * 16 = 96 ounces
Cost of 96 ounces of grapes = $18
Cost of 1 ounce of grape = 18/96
Cost of 72 ounces of grape = 18*72 / 96 = 27/2
= $13.50
Or
Direct Proportion because is weight increase, the cost will increase
96:18 = 72 : x
Product of means = Product of extremes
18*72 = x*96
18*72/96 = x
x =$13.50
Answer:
please mark me brainliesf if it is right
sin(A)/a = sin(B)/b
Answer:
The answer for this equation would be 1
Step-by-step explanation:
Hope I helped!
Answer:
500cm
Step-by-step explanation:
K.H.D.B.D.C.M
King henry died by drinking chocolate milk
they stand for
Kilometer, Hectometer, Decameter, Base, Decimeter, centimeter, millimeter
when you move to the right you multiply by ten
when moving to the left divide by ten
meter =base so since we move twice to the right we multiply by 100 since that is 10 times 10
100 times 5 =500cm
If i am right a thanks would be appreciated if wrong please leave a comment and i hope this helps u ;)
Answer:
College students' annual earnings is betweeen $2,514.33 and $3,907.67
Step-by-step explanation:
Hi, first, let´s introduce the formula that we need to use in order to find out the lower and higher limit of the interval.
Now, the only problem here is to find Z(alpha/2), so, let´s define that. Alpha is the remeining area of the normal distribution curve that is out of the limit, in other words, in this case, we need the 98% confidence interval, that means that 2% of the probs are going to be out of the range, therefore, this 2% is alpha. Since we need that the same area is removed from the left and right side of the uniform distribution curve, we need to find the value of Z in the uniform curve distribution table for 1% (that is 2%/2) and due to symmetry, we can now find the values of the interval (this means that we need the value of Z for 0.99, that is 2.33). Now, let´s find out the lower and higher limit of this interval.
So, the college students´annual earnings are between $2,514.33 and $3,907.67 with 98% of confidence.