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Alex73 [517]
3 years ago
14

I forgot to simplify

Mathematics
2 answers:
Serhud [2]3 years ago
6 0
\dfrac{4}{20} =  \dfrac{4 \div 4}{20 \div 4} =  \dfrac{1}{5}
makvit [3.9K]3 years ago
6 0
The Answer is 1/5 4 divided by four is one and 20 divided by four is 5
You might be interested in
the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the
Kitty [74]

Answer:

a+b+c=32

Step-by-step explanation:

we have

(-2x^{2} +x+31)+(3x^{2}+7x-8)

Adds the terms

Group terms that contain the same variable

(-2x^{2}+3x^{2})+(x+7x)+(31-8)

Combine like terms

(x^{2})+(8x)+(23)

where

a=1,b=8,c=23

therefore

a+b+c=1+8+23=32

8 0
3 years ago
14a - (2a +9)=2/3 (12a-18)​
Dmitrij [34]

Answer: a=-0.75

Step-by-step explanation:

14a - (2a +9)=2/3 (12a-18)​

14a - 2a -9=2/3 * 6(2a-3)​

12a-9=2*6/3 (2a-3)​

12a-9=2*2(2a-3)​

12a-9=4(2a-3)​

12a-9=8a-12

4a-9=-12

4a=-3

a=-3/4

a=-0.75

3 0
2 years ago
Read 2 more answers
In quadrilateral $ABCD$, we have $AB=3,$ $BC=6,$ $CD=4,$ and $DA=4$.
vampirchik [111]
The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}
8 0
3 years ago
You earned $75.70. You would like to buy some new T-shirts. Estimate the number of T-shirts you can buy if each one costs $10.80
Alex787 [66]
the answer is 7 t-shirts

divide 75.70 by 10.80

hope this helped :)
4 0
3 years ago
What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29

5 0
3 years ago
Read 2 more answers
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