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3 years ago

I forgot to simplify

Mathematics

2 answers:

Serhud [2]3 years ago

6 0

$\dfrac{4}{20} = \dfrac{4 \div 4}{20 \div 4} = \dfrac{1}{5}$

makvit [3.9K]3 years ago

6 0

The Answer is 1/5 4 divided by four is one and 20 divided by four is 5

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the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the

Kitty [74]

Answer:

$a+b+c=32$

Step-by-step explanation:

we have

$(-2x^{2} +x+31)+(3x^{2}+7x-8)$

Adds the terms

Group terms that contain the same variable

$(-2x^{2}+3x^{2})+(x+7x)+(31-8)$

Combine like terms

$(x^{2})+(8x)+(23)$

where

$a=1,b=8,c=23$

therefore

$a+b+c=1+8+23=32$

8 0

3 years ago

14a - (2a +9)=2/3 (12a-18)

Dmitrij [34]

Answer: a=-0.75

Step-by-step explanation:

14a - (2a +9)=2/3 (12a-18)

14a - 2a -9=2/3 * 6(2a-3)

12a-9=2*6/3 (2a-3)

12a-9=2*2(2a-3)

12a-9=4(2a-3)

12a-9=8a-12

4a-9=-12

4a=-3

a=-3/4

a=-0.75

3 0

2 years ago

Read 2 more answers

In quadrilateral $ABCD$, we have $AB=3,$ $BC=6,$ $CD=4,$ and $DA=4$.

vampirchik [111]

The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}

8 0

3 years ago

You earned $75.70. You would like to buy some new T-shirts. Estimate the number of T-shirts you can buy if each one costs $10.80

Alex787 [66]

the answer is 7 t-shirts

divide 75.70 by 10.80

hope this helped :)

4 0

3 years ago

What is the third quartile, Q3, of the following distribution?

GREYUIT [131]

Answer:

The third quartile is:

$Q_3=29$