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torisob [31]
3 years ago
14

The mean of 5,x,10,6,12 is 9. Find x

Mathematics
2 answers:
V125BC [204]3 years ago
6 0

Answer:

x = 12

Step-by-step explanation:

The mean calculated by adding all the numbers of a set and dividing it by the total number of numbers. In this case, we have five numbers, but we do not know what the sum of all the numbers is because one of the numbers in under the pronumeral x. The find this out we need to work backwards. We know that when all the five numbers are added we should get 45 (it is 9 time 5 as there are five numbers in the set). The next step is to subtract 45 from the number that we known (i.e. 45 - 5 - 10 - 6 - 12). This comes to 12.

<em>To double-check if you got the right answer you could add all five numbers include the 12 and divide it by 5 to see if the answer is 9.</em>

Wewaii [24]3 years ago
4 0

Answer:

<h2>12</h2>

Solution,

Summation FX= 5+10+6+12+X

=33+x

N(total no.of items)=5

Now,

Mean= summation FX/N

or 9=33+X/5

or 9*5=33+X ( cross multiplication)

or 45=33+X

or -x=33-45

or -x=-12

X=12

Hope this helps...

Good luck on your assignment..

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slope 4

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A student ate 3/20 of all candies and another 1.2 lb. Another student ate 35 of the candies and the remaining 0.3 lb. Altogether
Ipatiy [6.2K]
The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>

let
x-------> total <span>weight of candies
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x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
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6 lb
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Since the vertex of the quadratic is less than 0, the maximum value of the quadratic will be found at x=2, the end of the interval farthest from the vertex.

On the given interval, ...
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The products of the polynomials are:

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  • (x - y) * (x + 3y) = x² + 2xy + 3y²
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  • (x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6
  • (x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

<u>Pair 1: (xy + 9y + 2) and (xy – 3)</u>

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

<u>Pair 2: (2xy + x + y) and (3xy² - y)</u>

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

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(x - y) * (x + 3y)

Expand

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Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

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(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

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Expand

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Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

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Step-by-step explanation:

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