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Pavel [41]
3 years ago
7

What value of b will cause the system to have an infinite number of solutions?

Mathematics
2 answers:
NikAS [45]3 years ago
8 0
If the value of b is 6 then the system will have an infinite number of solutions since they will be the same lines.
ss7ja [257]3 years ago
5 0

Answer with explanation:

A system of equation will have infinite number of solution

if both the equation of line are coincident.

6 x - y=b

-3 x + y = -3

Line, ax + by=c

p x + q y =r,

are said to be coincident , if

\frac{a}{p}=\frac{b}{q}=\frac{c}{r}\\\\ \frac{6}{-3}=\frac{-1}{1}=\frac{b}{-3}\\\\{\text{as}} \frac{6}{-3}\neq\frac{-1}{1}

So,there is no real value of b for which , we can make the system of equation coincident or infinite umber of solutions.

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Which input value produces the same output value for
Natali5045456 [20]

Answer:

x=1

Step-by-step explanation:

it is the point of intersection of both lines which (1,1)

for x=1 both produce same value i.e.,1

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What is the range of f(x)=15(1/3)^x
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Step-by-step explanation:

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3 years ago
Help me on this please
Solnce55 [7]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

Using the normal distribution, it is found that the probabilities are given as follows:

a) 0.8871 = 88.71%.

b) 0.0778 = 7.78%.

c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1250 - 1140}{77.5}

Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

1 - 0.9222 = 0.0778 = 7.78%.

Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

Z = \frac{X - \mu}{s}

Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
Question 6(Multiple Choice Worth 3 points)
Marianna [84]
<h3>Answer:</h3>

A net is shown with 3 rectangles attached side by side all with width 2 centimeters. The length of the first and third rectangle is 9 centimeters and the middle is 7 centimeters. Attached to the middle rectangle below are 3 rectangles with a length of 7 centimeters. The width of these rectangles are 9 centimeters, 2 centimeters, and 9 centimeters.

<h3>Step-by-step explanation:</h3>

The area of a rectangular prism is the area of 6 surfaces. That is, 3 pairs of surfaces. Each of the three pairs will have one of the sets of dimensions ...

  • length × width
  • length × height
  • width × height

In order for a net to be a net useful for calculating the prism surface area, it must have 3 pairs of rectangles with these dimensions. The description above matches that requirement.

___

Please note that no two surfaces with the same pair of dimensions are adjacent.

4 0
3 years ago
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