Question

State how many imaginary and real zeros the function has.

Answer 1

Answer:

  2 imaginary; 2 real

Step-by-step explanation:

You can factor it as ...

  f(x) = (x^2 -16)(x^2 +1) . . . . . . . . . x^2-16 is the difference of squares

  = (x -4)(x +4)(x^2 +1)

The two linear factors have real zeros; the quadratic factor has two imaginary zeros. There are 2 imaginary and 2 real zeros.