State how many imaginary and real zeros the function has.

Mathematics

1 answer:

Klio2033 [76]3 years ago

8 0

Answer:

2 imaginary; 2 real

Step-by-step explanation:

You can factor it as ...

f(x) = (x^2 -16)(x^2 +1) . . . . . . . . . x^2-16 is the difference of squares

= (x -4)(x +4)(x^2 +1)

The two linear factors have real zeros; the quadratic factor has two imaginary zeros. There are 2 imaginary and 2 real zeros.

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<h2>Derive Surface Area of A Cylinder</h2>

If you take a look at a net of a cylinder, you can see it is composed of two circles(bases) and a rectangular strip with the length of the diameter of the circle

The formula for the area of a circle = πr², and since there are 2, it is 2πr²

The formula for circumference of a circle = 2πr, and since we are multiplying that by the height by the height of the cylinder, it is 2πrh

∴ 2πr² + 2πrh