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4 years ago

When you multiply 2/3 by a fraction less than one, how does the product compare to the facotrs

Mathematics

2 answers:

ss7ja [257]4 years ago

4 0

Multiply by 1/9 and divided by 1/9

klasskru [66]4 years ago

4 0

Multiply 1/9 by 1/9 to get the answer

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The graph of 15x + 7y = 15 is shown on the grid. Which ordered pair is in the solution set of 15x + 7y ≥ 15?

elena55 [62]

Answer:

The correct option is c.

Step-by-step explanation:

The given equation is

$15x+7y=15$

The given inequality is

$15x+7y\geq 15$

A point will contained in solution set if the above inequality satisfied by that point.

Check the point (0,-3),

$15(0)+7(-3)\geq 15$

$-21\geq 15$

This statement is false, therefore option a is incorrect.

Check the point (-3,0),

$15(-3)+7(0)\geq 15$

$-45\geq 15$

This statement is false, therefore option b is incorrect.

Check the point (3,3),

$15(3)+7(3)\geq 15$

$66\geq 15$

This statement is true, therefore option c is correct.

Check the point (-3,-3),

$15(-3)+7(-3)\geq 15$

$-66\geq 15$

This statement is false, therefore option d is incorrect.

7 0

3 years ago

Which ordered pair is a solution of the equation -3x - y = 6

e-lub [12.9K]

Hello there!

The correct answer is option B (-3,3)

-3x - y = 6

-3(-3) - 3 = 6

9 - 3 = 6

6 = 6

Thus, the correct answer is option B

Good luck with your studied!

8 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

Kevin plans to put concrete on a rectangular portion of his driveway the portion is 10 feet long and 3 inches high the price of

Fudgin [204]

First we need to know the total volume of concrete used:
$V_total = \frac{cost_{total}}{cost{unit}}$
$V_total = \frac{\$72.98}{\frac{\$90}{yd^{3}}}$
$V_total = 0.7407yd^{3}$

Now we can use the formula for volume of a rectangular prism:
$V=lwh$
Convert everythig to yards and substitute:
$0.7407yd^{3}=(3.33yd)(w)(0.08333yd)$
$w=\frac{0.7407}{3.33 \times 0.08333}$
$w \aprox 2.66yd$

5 0

3 years ago

Interpret the y-intercept of the graph

Svetlanka [38]

Answer:

answer is A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers