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3 years ago

Open the linkkkk plzz

Mathematics

1 answer:

borishaifa [10]3 years ago

8 0

A=1/2Base*Height
A=1/2(18)(24)
A=216
216 is 9 times larger than 24'
B

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Find the area of the shaded region.

tensa zangetsu [6.8K]

Answer:

180

Step-by-step explanation:

triangle: 1/2bh = 1/2 24x24 = 288

rectangle : 18x6 = 108

288-108 = 180in ^2

8 0

2 years ago

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Find two numbers whose difference is 154 and whose product is a minimum.

Serggg [28]

Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x

we need to find the minimum value of z

z' = 2x + 154 which = zero for minm or maxm value

x = -77 and y = 154 -77 = 77

so the 2 numbers are -77 and 77

7 0

3 years ago

How much should each person receive?

seraphim [82]

Add up the 13+12 to get 25 then divide 500,000 by 25 to get 2,000. Then multiply it by 13 to get 26000 and by 12 to get 24000. Subtract 26000 minus 24000 to get 2000. 2000 is your answer.

4 0

2 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

2 years ago

Add the two expressions.

Vladimir79 [104]

Your answer will be 3.7w-2

8 0

3 years ago

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