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abruzzese [7]
3 years ago
5

Open the linkkkk plzz

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0
A=1/2Base*Height
A=1/2(18)(24)
A=216
216 is 9 times larger than 24'
B
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Helppp!! I NEED HELP PLEASE
Elodia [21]

Given:

The table of values for the function f(x).

To find:

The values f^{-1}(f(3.14)) and f(f(-7)).

Solution:

From the given table, it is clear that the function f(x) is defined as:

f(x)=\{(-14,11),(-7,-12),(-12,-5),(9,1),(10,-2),(-2,13)\}

We know that if (a,b) is in the function f(x), then (b,a) must be in the function f^{-1}(x). So, the inverse function is defined as:

f^{-1}(x)=\{(11,-14),(-12,-7),(-5,-12),(1,9),(-2,10),(13,-2)\}

And,

f^{-1}(f(a))=f^{1}(b)

f^{-1}(f(a))=a              ...(i)

Using (i), we get

f^{-1}(f(3.14))=3.14

Now,

f(f(-7))=f(-12)

f(f(-7))=5

Therefore, the required values are f^{-1}(f(3.14))=3.14 and f(f(-7))=5.

5 0
3 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
Dora buys one package each of 1lb 2 lb and 4 lb packages of ground beef to make hamburgers. How many 1/4 lb hamburgers can she m
Katarina [22]
1+2+4= 7 lbs. she can make 28 1/4 lb burgers
4 0
3 years ago
What is the answer for the last 2 questions
arsen [322]
A. is 20ft I believe but I don't know the other one

5 0
3 years ago
Properties of exponents<br> Rewrite the expression in the form b^n—— (b^2)^3/7
exis [7]

Answer:

b^{\frac{6}{7}}  is the required expression.

Step-by-step explanation:

(b^2)^{\frac{3}{7}}\\\\\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0\\\\=b^{2\cdot \frac{3}{7}}\\\\=b^{\frac{6}{7}}

Best Regards!

3 0
3 years ago
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