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ryzh [129]
3 years ago
12

50 POINTS!!! I WILL GIVE BRAINLIEST!!!!!

Mathematics
2 answers:
dedylja [7]3 years ago
6 0

Sixteen more than twice a number m is 36:

2m + 16 = 36      <em>subtract 16 from both sides</em>

2m = 20       <em>divide both sides by 2</em>

<h3>m = 10</h3>
dedylja [7]3 years ago
3 0

The equation would be worded as: 2m+16=36.


Solve! Using the subtraction property of equality, 2m=20. Then the division property of equality lets us figure out that m=10.

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SHOW YOUR WORK!!!!!!!!!!!!!!!!!!!
Oduvanchick [21]

Answer:

My Answer: <u>33.95</u>

Step-by-step explanation:

x - 13.75 = 20.2

so because it is subtracting we have to add.

x - 13.75 + 13.75 = 20.2 + 13.75

when added, x will cancel out, and we will be left with the answer.

x = 33.95

GL!

-Oceaniii

3 0
3 years ago
In the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord?
erma4kov [3.2K]
A  about 12 feet is the lenth of the cord

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3 years ago
sam goes to the market to buy a hamburger for cookout. he buys 3 3/4 pounds if a hamburger. how many 1/4 pound patties can he ma
Alexandra [31]
3 3/4÷ 1/4
15/4÷1/4
15/4÷4/1
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7 0
3 years ago
ANOTHER ONE AGAIN PLSSSSS
mina [271]

Answer:

Luka had 6 slices, Kira had 9 slices and Ali 12 slices

Step-by-step explanation:

Each had 2/3 of their slices hence

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6 0
3 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
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