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dimaraw [331]
3 years ago
12

The graph below shows the air temperature over a 10 hour period from noon until 10 PM which is true based on the graph?

Mathematics
2 answers:
Sav [38]3 years ago
7 0
B. the temperature change between noon and 6 PM is the same as the temperature change between 8 PM and 10 PM.
Usimov [2.4K]3 years ago
3 0

Answer:

B. Temperature change between noon and 6 PM is the same as the temperature change from 8 PM until 10 PM

Step-by-step explanation:

Based on graph lets understand the options:

A. The temperature changes greater per hour from noon until 6 PM then from 8 PM until 10 PM  : This is false.

We can see that temperature at noon is 60 degrees and at 2 pm it is around 50 degrees and at 6 pm the temperature is around 40 degrees. At 8 pm the temperature is 40 degrees and at 10 pm it is about 20 degrees.

B. Temperature change between noon and 6 PM is the same as the temperature change from 8 PM until 10 PM. This is true.

Please refer to the explanation above. The temperature changed approx 20 degrees in both cases.

C. The temperature remains constant between noon and 6 PM. This is false. There are changes in temperature.

D. The temperature remains constant between 8 PM and 10 PM. This is also false.

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SVEN [57.7K]

Answer:

1st graph: D) Y = 2/3x

2nd graph: A) Y = 4/3x - 5

Step-by-step explanation:

Hope this helps. Pls give brainliest!

6 0
3 years ago
Read 2 more answers
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liberstina [14]

3 = X/2 + 2

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Jan had 2 pencils to start off with. She gave half (1 pencil) to Talia. Her brother gave her 2, which means she ends up with 3.

8 0
3 years ago
PQ is parallel to RS. The length of RP is 4cm; the length of PT is 16cm; the length of QT is 20cm. What is the length of SQ?
Step2247 [10]
Hello,

Using the theorem of Thalès,
PR/TP=QS/TQ==>QS=4*20/16=5

Answer A
3 0
3 years ago
Pls help :Find the missing side or angle.<br> Round to the nearest tenth.
Nitella [24]

Answer:

C° = 71.6056

Step-by-step explanation:

Law of Cosines: c² = a² + b² - 2abcosC°

Step 1: Plug in known variables

29² = 30² + 15² - 2(30)(15)cosC°

Step 2: Evaluate

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3 years ago
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(-2g^3h)(-3gj^4)^2(-ghj)^2
ratelena [41]

QUESTION -

(-2g^3h)(-3gj^4)^2(-ghj)^2

ANSWER -

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3 years ago
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