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3 years ago

What is the domain of the function below?

Mathematics

2 answers:

amm18123 years ago

8 0

$f(x)=\log(x-4)+4\\\\The\ domain:\\\\x-4 > 0\qquad\text{add 4 to both sides}\\\\x > 4\\\\Answer:\ \boxed{x > 4\to x\in(4,\ \infty)}\to\boxed{D.}$

natulia [17]3 years ago

3 0

Answer:

(4, oo)

Step-by-step explanation:

i just took the test on plato and it is he correct answer if you have any more questions dm me personally and ill try to help!!! hopefully this helps

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Find the minimum or maximum value of the function. What is the H? (Desmos)

beks73 [17]

Answer:

Minimum: (2,4)

Step-by-step explanation:

h(x)=3( $x^{2}$ -4x)+16

=3( $x^{2}$ -4x+4-4)+16 (- For the balance of equation, and attention 1)

=3 $(x-2)^{2}$ -3*4+16

=3 $(x-2)^{2}$ +4

<h3>Attention:</h3>

1. $(a-b)^{2}=a^{2} -2ab+b^{2}$

2. The formula for the vertex form is y = $a(x-h)^{2}+k$ , the vertex is (h,k)

4 0

3 years ago

Camila and her children went into a grocery store and where they sell apples for $0.50 each and mangos for $0.75 each. Camila ha

german

Maximum number of mangoes that Camila can buy are 5

Step-by-step explanation:

Step 1: Find the cost of 8 apples bought by Camila.

Cost of 1 apple = $0.50

Cost of 8 apples = $0.50 × 8 = $4

Step 2: Find the remaining amount with Camila after she bought 8 apples.

Total amount that can be spent = $7.75

Cost of apples = $4

Remaining amount = $7.75 - $4 = $3.75

Step 3: Find the number of mangoes she can buy

Cost of 1 mango = $0.75

Number of mangoes = $3.75/$0.75 = 5

8 0

3 years ago

12 more than m machines

Gelneren [198K]

Answer:

m+12

Step-by-step explanation:

m+12

8 0

3 years ago

The endpoints of one diameter of a circle are (9,3) and (-5,15). What is the center of the circle?

fiasKO [112]

Answer:

(2,9)

Step-by-step explanation:

X midpoint:9+(-5)/2 which gives 2

Y midpoint:3+15/2 which gives 9

7 0

3 years ago

Solve for (a+1)/2=1/a.

LenKa [72]

Hello!

To solve this, you are trying to convert one side to a quadratic equation and the other to just 0. Then, solve the equation.

----

First, move the /2 to the other side of the equation.

(a+1)/2 = 1/a

a+1 = 2/a

Next, multiply both sides by a.

a+1 = 2/a

$a^{2} +a=2$

And then subtract both sides by 2. This will get you to a quadratic equation.

$a^{2} +a=2$

$a^{2} +a-2=0$

Now, factor the equation. When we're factoring, we are looking for the form (a + b)(a + c), where b + c must equal 1 (the coefficient of a) and b*c must equal -2. In this case, b = 2, and c = -1.

Therefore:

$a^{2} +a-2=0$

(a + 2)(a - 1) = 0

To get the answer, recall that anything multiplied by 0 is equal to 0. Therefore, to get the left side to equal 0, either (a + 2) or (a - 1) must equal 0. To do this, a must either be -2 or 1.

Therefore, a = -2, or a = 1.

----

Check your work:

(-2 + 1)/2 = 1/-2

-1/2 = -1/2

(1 + 1)/2 = 1/1

2/2 = 1/1

1 = 1

----

Hope this helps!

6 0

3 years ago