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o-na [289]
3 years ago
10

Natalie walked 35 mile in 12 hour. How fast did she walk, in miles per hour? A. 310 mile per hour B. 56 mile per hour C. 115 mil

es per hour D. 2 miles per hour
Mathematics
2 answers:
vichka [17]3 years ago
6 0
2 miles per hour
Hope this helps
Paha777 [63]3 years ago
5 0
12 hours = 35 miles
1 hour = 35 / 12
= 2.91666667 miles
= 2 miles per hour.

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The bakery made 92 muffins 17 or a blueberry 23 with cranberry and the rest of the chocolate chip how many chocolate chip muffin
astra-53 [7]
If there are 92 muffins in total and 17 are blueberry, and 23 are cranberry then the remaining muffins (chocolate chip) is 52 muffins.
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3 years ago
How many combinations with repetition are allowed if n = 8 and r = 4?
igor_vitrenko [27]
Hello, the answer you are looking for should be “330” combinations :)

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3 years ago
Which graph represents this system?<br> answers below A.B.C or D first one is the system
hodyreva [135]

Answer:

A

Step-by-step explanation:

Both functions are the same Just find the value of y and you will get the same equation

Only A is correct

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3 years ago
The Tetrahedron Superyacht designed by Jonathan Schwinge is a regular tetrahedron with edges 20 m long. The distance r from one
Pavel [41]
The answer is 16.36 meters
4 0
3 years ago
Read 2 more answers
How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
3 years ago
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