Answer:
(a)![\log_3(\dfrac{81}{3})=3](https://tex.z-dn.net/?f=%5Clog_3%28%5Cdfrac%7B81%7D%7B3%7D%29%3D3)
(b)![\log_5(\dfrac{625}{25})=2](https://tex.z-dn.net/?f=%5Clog_5%28%5Cdfrac%7B625%7D%7B25%7D%29%3D2)
(c)![\log_2(\dfrac{64}{8})=3](https://tex.z-dn.net/?f=%5Clog_2%28%5Cdfrac%7B64%7D%7B8%7D%29%3D3)
(d)![\log_4(\dfrac{64}{16})=1](https://tex.z-dn.net/?f=%5Clog_4%28%5Cdfrac%7B64%7D%7B16%7D%29%3D1)
(e)![\log_6(36^4)=8](https://tex.z-dn.net/?f=%5Clog_6%2836%5E4%29%3D8)
(f)![\log(100^3)=6](https://tex.z-dn.net/?f=%5Clog%28100%5E3%29%3D6)
Step-by-step explanation:
Let as consider the given equations are
.
(a)
![\log_3(\dfrac{81}{3})=\log_3(27)](https://tex.z-dn.net/?f=%5Clog_3%28%5Cdfrac%7B81%7D%7B3%7D%29%3D%5Clog_3%2827%29)
![\log_3(\dfrac{81}{3})=\log_3(3^3)](https://tex.z-dn.net/?f=%5Clog_3%28%5Cdfrac%7B81%7D%7B3%7D%29%3D%5Clog_3%283%5E3%29)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(b)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(c)
![\log_2(\dfrac{64}{8})=\log_2(8)](https://tex.z-dn.net/?f=%5Clog_2%28%5Cdfrac%7B64%7D%7B8%7D%29%3D%5Clog_2%288%29)
![\log_2(\dfrac{64}{8})=\log_2(2^3)](https://tex.z-dn.net/?f=%5Clog_2%28%5Cdfrac%7B64%7D%7B8%7D%29%3D%5Clog_2%282%5E3%29)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(d)
![\log_4(\dfrac{64}{16})=\log_4(4)](https://tex.z-dn.net/?f=%5Clog_4%28%5Cdfrac%7B64%7D%7B16%7D%29%3D%5Clog_4%284%29)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(e)
![\log_6(36^4)=\log_6((6^2)^4)](https://tex.z-dn.net/?f=%5Clog_6%2836%5E4%29%3D%5Clog_6%28%286%5E2%29%5E4%29)
![\log_6(36^4)=\log_6(6^8)](https://tex.z-dn.net/?f=%5Clog_6%2836%5E4%29%3D%5Clog_6%286%5E8%29)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(f)
![\log(100^3)=\log((10^2)^3)](https://tex.z-dn.net/?f=%5Clog%28100%5E3%29%3D%5Clog%28%2810%5E2%29%5E3%29)
![\log(100^3)=\log(10^6)](https://tex.z-dn.net/?f=%5Clog%28100%5E3%29%3D%5Clog%2810%5E6%29)
![[\because \log10^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog10%5Ex%3Dx%5D)
D.The puppy gains approximately 0.25 pound each week.
<u>x = no. of weeks</u> in f(x) = 0.25x + 1.2
Answer:
12.8767123288% so maybe 12.9
Step-by-step explanation:
Answer:
Step-by-step explanation:
the graph moves down one unit
if you add/subtract outside the parent function the graph moves up/down