Answer:
Cos A = 3/5
Step-by-step explanation:
Points to remember
<u>Trigonometric ratios
</u>
Sin θ = Opposite side/Hypotenuse
Cos θ = Adjacent side/Hypotenuse
Tan θ = Opposite side/Adjacent side
From the figure we can see a right angled triangle, ABC
AC = 9, CB = 12 and AB = 15
<u>To find the value of Cos A</u>
Cos A = Adjacent side/Hypotenuse
= AC/AB
= 9/15 = 3/5
Therefore the value of Cos A = 3/5
Answer:
SinA = √5/3
CosB = √5/3
Step-by-step explanation:
First let us find the value of a. This is illustrated below:
a^2 = 6^2 — 4^2
a^2 = 36 — 16
a^2 = 20
Take the square root of both side
a = √20 = √(4 x 5) = √4 x √5
a = 2√5
From the diagram,
For sinA
Opp = 2√5
Hypo = 6
Adj = 4
SinA = opp /Hypo
SinA = 2√5/6
SinA = √5/3
For CosB
Opp = 4
Hypo = 6
Adj = 2√5
CosB = Adj /Hypo
CosB = 2√5/6
CosB = √5/3
Answer:
37/3
Step-by-step explanation:
Answer:
The left
Step-by-step explanation:
4×3=12-5=7
7=7