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serious [3.7K]
2 years ago
11

which of these expressions or phrases can be used to represent the model? Choose ALL of the correct answers iready

Mathematics
2 answers:
Rama09 [41]2 years ago
8 0
If you can put them down we can help you
Pepsi [2]2 years ago
4 0
Well...what are the expressions and phrases???
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Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
2 years ago
Diego solved an equation by multiplying both sides of the equation by 6. Then he checked that 6 is the correct solution by subst
Nikolay [14]
Based on the given condition Diego utilized, it can be said that he used multiplication property when he multiplied both sides of the equation by 6 and then substitution property when he substituted 6 to the original equation.
(c) Multiplication property of equality and substitution property of equality
7 0
3 years ago
A collection of five coins has a value of $1 and consists of dimes and
DENIUS [597]

For this case we propose a system of equations. We have to:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of quaters

We know that:

One dime equals 10 cents, $0.10

A quater equals 0.25 cents, $0.25

According to the statement we have:

x + y = 5\\0.10x + 0.25y = 1

We multiply the first equation by -0.10:

-0.10x-0.10y = -0.5

We have the following equivalent system:

-0.10x-0.10y = -0.5\\0.10x + 0.25y = 1

We add the equations:

-0.10x + 0.10x-010y + 0.25y = -0.5 + 1\\0.15y = 0.5\\y = \frac {0.5}{0.15}\\y = 3.33

Approximately 3 quater coins

x = 5-y = 5-3 = 2

And two dimes

Answer:

3 quater

2 dimes

4 0
2 years ago
Solve i=Prt for t, if i=105,p=700,and r=0.05
Katen [24]
3675. You multiply 105 700, then you multiply the answer by 0.05.
5 0
3 years ago
Read 2 more answers
Kirk went to a friend’s house after dinner. He left his house at 7:29pm and returned home at 8:05pm. How long was Kirk gone for?
liberstina [14]

Answer:

36 minutes

Step-by-step explanation:you look at it and solve it

3 0
3 years ago
Read 2 more answers
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