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FrozenT [24]
3 years ago
6

Is 16x2 + 24x + 9 a perfect square trinomial

Mathematics
1 answer:
fredd [130]3 years ago
5 0
16x²=(4x)², 9=3², 24x=2*4x*3
so this is a perfect square: (4x+3)² 
You might be interested in
One angle in a complementary pair of angles measures 3 times the other angle.
GuDViN [60]

Answer:

22.5 degrees

Step-by-step explanation:

Complementary angles add up to be 90 degrees. You can model the simple equation x+3x=90 where is x is the small angle and 3x is the large angle.

4x=90\\x=22.5

the smaller angle is 22.5 degrees

4 0
3 years ago
Consider the line 7x+9y=5
alisha [4.7K]

Answer:

The slope of a line parallel to this line will be: -7/9

The slope of the perpendicular line will be:

\frac{-1}{\frac{-7}{9}}=\frac{9}{7}

Step-by-step explanation:

We know the slope-intercept form

y=mx+b

Here,

  • m is the slope
  • b is the y-intercept

Given the equation

7x+9y=5

simplifying to write in the lope-intercept form

y=-\frac{7}{9}x+\frac{5}{9}

Thus, the slope of the line is: -7/9

The slope of a line parallel to the line:

We have already determined that the slope of the line is: -7/9

  • We know that the parallel lines have the same slope.

Thus, the slope of a line parallel to this line will be: -7/9

The slope of a line perpendicular to the line:

We have already determined that the slope of the line is: -7/9

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus,  the slope of the perpendicular line will be:

\frac{-1}{\frac{-7}{9}}=\frac{9}{7}

4 0
3 years ago
Please solve this equation<br> P= a=96<br> a= P-16<br> P=4+6
Softa [21]

Answer:

Sorry

Step-by-step explanation:

I don't know the answer

5 0
3 years ago
Can a triangle have sides with the given​ lengths? Explain.
Nookie1986 [14]
No because when you add any 2 sides the answer has to be bigger than the 3rd side

ex: 2+7=9
9 is too small, so the tips of the side that is 2ft would not touch the side that is 7ft
4 0
3 years ago
Suppose that f: R --&gt; R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
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