x = -3 → -3 = -3 and -3 < 4 therefore -3 ≤ -3 ≤ 4
x = -2.2 → -3 < -2.2 and -2.2 < 4 therefore -3 ≤ -2.2 ≤ 4
x = -2 → -3 < -2 and -2 < 4 therefore -3 ≤ -2 ≤ 4
x = 0 → -3 < 0 and 0 < 4 therefore -3 ≤ 0 ≤ 4
x = 1.5 → -3 < 1.5 and 1.5 < 4 therefore -3 ≤ 1.5 ≤ 4
x = 3 → -3 < 3 and 3 < 4 th≤erefore -3 ≤ 3 ≤ 4
x = 4 → -3 < 4 and 4 = 4 therefore -3 ≤ 4 ≤ 4
(X-3)*log(1/2)=(x-5)*log(1/4)
X-3=(log(1÷4)÷log(1÷2))*(x-5)
X-3=2(x-5)
X-3=2x-10
X-2x=3-10
-x=-7
X=7
5 is in the thousands place. 6 is in the hundreds place. 7 is in the tens place. 8 is in the ones place. 3 is in the tenths place. 2 is in the hundreths place. 1 is in the thousandths place.
Answer:
15
Step-by-step explanation:
Given that a1 = 6
an = 3 + 2(an-1),
Substitute n = 2 into the formula
a2 = 3 + 2(a1)
a2 = 3 + 2(6)
a2 = 3+12
a2 = 15
Hence the second term of the sequence is 15
Answer:
y=-1x+8
Step-by-step explanation:
idk what to do here
