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2 years ago

Order the following from least to greatest: |5|, -4, -|9|, -(-1), |-10|, -2.72

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

7 0

Answer:

-|9|, -4, -2.72, -(-1), |5|, |-10|

Step-by-step explanation:

numbers with | | around them have everything removed but the number.

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-6x + 18 = 7- (4x + 9) help will give brainlyist

andreyandreev [35.5K]

Answer:

X = -5

Step-by-step explanation:

-6x + 18 = 7 - (4x + 9)

first we simplify the parentheses.

distribute the invisible number one created by the negative sign in front of the parentheses to get -6x + 18 = 7 - 4x - 9

then simplify further by subtracting 9 from the right side, leaving you with

-6x + 18 = -2 - 4x

next, add 2 to both sides to isolate the variable.

-6x + 20 = -4x

then, to isolate the variable further add 6x to both sides.

20 = -4x

divide both sides by -4 to isolate the variable

-5 = x

so, x = -5

6 0

3 years ago

Read 2 more answers

If ∠A and ∠B are supplementary and m∠A = 37°45', then m∠B = ______.

xenn [34]

Answer: 142°15'

Explanation:

Supplementary angles are angles that add up to make a straight angle ( $180^{\circ}$ ).

Therefore, we must find the angle ∠B such that

∠A + ∠B = 180° (1)

We know that ∠A = 37°45', so we can re-arrange equation (1) to find the magnitude of ∠B:

∠B = 180° - ∠A = 180° - 37°45' = 142°15'

So, the correct answer is

142°15'

6 0

3 years ago

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What percent of 17 is 51?

Taya2010 [7]

Answer:

33%

Step-by-step explanation:

h steps:

Step 1: We make the assumption that 51 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=51$.

Step 4: In the same vein, $x\%=17$.

Step 5: This gives us a pair of simple equations:

$100\%=51(1)$.

$x\%=17(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{51}{17}$

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{17}{51}$

$\Rightarrow x=33.33\%$

Therefore, $17$ is $33.33\%$ of $51$.

4 0

2 years ago

Read 2 more answers

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

PQ is parallel to RS. The length of RP is 4cm; the length of PT is 16cm; the length of QT is 20cm. What is the length of SQ?

Step2247 [10]

Hello,

Using the theorem of Thalès,
PR/TP=QS/TQ==>QS=4*20/16=5

Answer A

3 0

3 years ago