Vertex=(-1,0)
x^2-2x-1
y=− ( x + 1 )^2 + 0
Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.
Find the vertex (h,k) = (-1,0)
I believe that it’s the first one
Answer:
2
1/3
Step-by-step explanation:
A(xA, yA) = A (3,1)
B(xB,yB)=B(5,5)
the gradient=(yB-yA)/ (xB-xA)=(5-1)/(5-3)=4/2=2
C(4,7),D(10,9)
the gradient=(yD-yC)/(xD-xC)=(9-7)/(10-4)=2/6=1/3
Answer:
2⁴
Step-by-step explanation:
4² would be 4x4 not 2x2x2x2
2x2x2x2 would be 2⁴.
