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3 years ago

Can you tell me the statements that are true?

Mathematics

1 answer:

Vesnalui [34]3 years ago

4 0

Answer:

1=true

2=false

3=false

4=true

5=true

6=false

Step-by-step explanation:

hope this helps!:)

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Please help with these questions!

Colt1911 [192]

1/8 + 6/8 = 7/8
17 11/13 - 9 7/13 = 8 4/13
2/8 + 4/8 = 6/8 = 3/4
8/4 + 1/4 = 9/4 = 2 1/4
9/10 + 3/10 = 12/10 = 1 1/5
2 - 3/5 = 10/5 - 3/5 = 7/5 = 1 2/5
3/4 * 4 = 12/4 = 3
1/4 * 6 = 6/4 = 1 1/2

8 0

3 years ago

a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and

fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

$x(t) = -4.9t^{2} + 9.8t$

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format $x(t) = at^{2} + bt + c$

The vertex is the point $(t_{v}, x(t_{v}))$ , in which

$t_{v} = -\frac{b}{2a}$

In this question:

$x(t) = -4.9t^{2} + 9.8t$

So $a = -4.9, b = 9.8$

Vertex:

$t_{v} = -\frac{9.8}{2*(-4.9)} = 1$

The time taken for the upward motion is 1 second.

$x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9$

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

$-4.9t^{2} + 9.8t = 0$

$4.9t^{2} - 9.8t = 0$

$4.9t(t - 2) = 0$

$4.9t = 0$

$t = 0$

$t - 2 = 0$

$t = 2$

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0

3 years ago

Fred got a score of 80 on the test. Enter a division sentence using negative numbers where the quotient represents the number of

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

For ΔABC, ∠A = 3x, ∠B = 2x - 3, and ∠C = x + 3. If ΔABC undergoes a dilation by a scale factor of 2 to create ΔA'B'C' with ∠A' =

Mashutka [201]

I am not 100% sure but I think the answer is C I hope I helped you and Good luck

3 0

4 years ago

Read 2 more answers

cinema A sells a twelve pack of moive passes for $66. Cinema B selles a five pack of moive passes for $28. Find the cost per moi

nekit [7.7K]

CINEMA A sells each movie pass for $5.50, and CINEMA B sells each movie pass for $5.60.

To find the cost of each pass in Cinema A, all you would have to do it divide 66 by 12, where you would get 5.5, which in other words would be $5.50. And to find the cost of each pass in Cinema B, you wound divide 28 by 5,and you would get 5.6, which is in other words, $5.60.

5 0

4 years ago