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3 years ago

Alyssa observes a chemical reaction between an atom of Be and an atom of Se.

Chemistry

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer;

-Beryllium selenide

Explanation;

-The chemical name of the compound produced by the reaction is Beryllium selenide.

Beryllium reacts with Selenium to form Beryllium Selenide according to the equation;

Be(s) + Se = BeSe (s)

The Beryllium selenide molecule contains a total of 1 bond(s). There are 1 non-H bond(s), 1 multiple bond(s) and 1 double bond(s).

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1. Which is a chemical property of wood? conductivity flammability malleability

Allisa [31]

Answer:

Wood consists mainly of organic substances (99% of the total mass). Elemental chemical composition of wood of different breeds is practically the same. Absolutely dry wood on average contains 49% of carbon, 44% of oxygen, 6% of hydrogen, 0.1-0.3% of nitrogen. When burning wood remains its inorganic part - ash.

So the answer is flammability because wood is flammable.

3 0

3 years ago

If a gas is compressed from 4 L to 1 L and the temperature remains constant, what happens to the pressure?

Luba_88 [7]

If T=const
P1V1=P2V2
P1*4L=P2*1L
P2=4P1
pressure increases by factor of 4

4 0

3 years ago

Read 2 more answers

Using your value of Ksp, and starting with an equilibrium system consisting of a saturated solution of calcium hydroxide, predic

Ugo [173]

Answer:

(A) $HNO_{3}$ Solubility will increase.

(B) $NaOH$ Solubility will decrease.

(C) $Ca(NO_{3} )_{2}$ Solubility will decrease.

Explanation:

a) According to Le Chatelier's Principle when a change is introduced in a reaction system at equilibrium, the system responds by the reaction shifting in the direction to counter the change introduced.

When the change introduced is addition of acid, some $OH^{-}$ are consumed due to it and the system would respond by reaction shifting towards creation of more $OH^{-}$ in the system by increased dissolution. Thus solubility increase.

(b) When $OH^{-}$ are added, the reaction shifts to counter the change introduced of increased $OH^{-}$ by shifting to side that decreases the increased $OH^{-}$ . That happens by reaction shifting towards some $Ca (OH)_{2}$ precipitating back. Hence solubility decreases.

(c) The change introduced is addition of $Ca^{2+}$ which will be countered by reaction shifting to side that decreases increased $Ca ^{2+}$ , which happens by some $Ca(OH)_{2}$ precipitating back. Hence solubility decreases.

6 0

4 years ago

a mixture of emanations from radioactive atoms is passed through electrically charged plates imagination number one is attracted

slava [35]

Hello there!

The nuclear emanations 1, 2 and 3 are called, respectively:

1) Alpha, beta and gamma

Alpha Radiation consists of two protons and two neutrons, as protons are positive particles, they will be attracted to the negatively charged plate.

Beta Radiation is composed of a high-energy electron. As electrons are negative particles, they will be attracted to the positively charged plate.

Gamma Radiation is composed or photons. Photons don't have charge or mass, and they will not be attracted to the charged plates. This kind of radiation is more penetrating than the other two.

Have a nice day!

3 0

3 years ago

2.122 g of a solid mixture containing only potassium carbonate (FW = 138.2058 g/mol) and potassium bicarbonate (FW = 100.1154 g/

aleksandr82 [10.1K]

Answer:

The weight percent of potassium carbonate is 50,8 wt% and of potassium bicarbonate 49,2 wt%

Explanation:

The reactions of potassium carbonate (K₂CO₃) and potassium bicarbonate (KHCO₃) with HCl produce:

K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O

KHCO₃ + HCl → KCl + CO₂ + H₂O

That means that you need 2 moles of HCl to titrate potassium carbonate and 1 mol to titrate potassium bicarbonate.

The moles of HCl to titrate the mixture are:

0,03416L× $\frac{0,762mol}{1L}$ = 0,02603 mol of HCl

If X is mass of K₂CO₃ and Y is mass of KHCO₃ in the mixture, the moles of HCl to titrate the mixture are equals to:

0,02603 mol = 2X× $\frac{138,2058 g}{1mol}$ + Y× $\frac{100,1154 g}{1mol}$ (1)

As the mass of the mixture is 2,122g:

2,122g = X + Y (2)

Replacing (2) in (1):

0,02603 mol = 0,01447 (2,122-Y) + 9,988x10⁻³Y

0,02603 mol = 0,0307 - 0,01447Y + 9,988x10⁻³Y

-4,6778x10⁻³ = -4,4827x10⁻³Y

1,044g = Y -mass of potassium bicarbonate-

Thus:

X = 1,078g -mass of potassium carbonate-

The weight percent of potassium carbonate is:

$\frac{1,078g}{2,122g}$ ×100 = 50,8 wt%

The weight percent of potassium bicarbonate is:

$\frac{1,044g}{2,122g}$ ×100 = 49,2 wt%

I hope it helps!

5 0

3 years ago