Answer:
18m/s
Explanation:
Given parameters;
Initial velocity = 10m/s
Acceleration = 2m/s²
Time = 4s
Unknown:
Car's new velocity = ?
Solution:
We use one of the kinematics equation to solve this problem:
v = u + at
v = new velocity
u = initial velocity
a = acceleration
t = time
v = 10 + (2 x 4) = 18m/s
The approximate molar mass of lauryl alcohol is 183 g/mol.
As per Raoult's law:
Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.
/M = where ml is the mass of lauryl alcohol and ms is the mass of the solvent.
=K/M
Therefore, M===183 g/mol.
<h3>Lauryl alcohol </h3>
An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers. Lauryl alcohol is a kind of emollient used in cosmetics. Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.
A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?
Learn more about lauryl alcohol here:
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Answer:
The heat that must be supplied is 298.1 kJ
Explanation:
We must apply the calorimetry formula to solve this.
Q = m . C . ΔT
where Q is heat, m is the mass, C is the specific heat and ΔT the difference between Final temperature and Initial temperature.
The normal boiling point of water is 100° so ΔT = (100° - 20°)
Notice that units in specific heat are J/ g.K so temperature should be in K but in this case K and C are the same, because it is a difference.
T°K = T°C + 273
ΔT = (100° - 20°) = 80°
ΔT = (373° - 293°) = 80°
750g . 0.51 J/gK . 80K + 800g . 4.18 J/gK . 80K = 298120 J
Ur answe is c hope u get it correct ..
Answer:
330.75 cm^3
Explanation:
d=m/v
10.5g/1 cm^3=31.5g/x cm^3
solve for x
round to the sig figs you have to.