Answer:
Step-by-step explanation:
![f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20-%201%20%7D%20%283%20%7Bx%7D%5E%7B2%7D%20%20-%200%29%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%20-%203%7D%7B3%7D%20%20%7D%20%20%5Ctimes%203%20%7Bx%7D%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%202%7Bx%7D%5E%7B2%7D%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%20-%201%7D%7B3%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%201%7D%7B3%7D%20%20%7D%20%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%20%5Csqrt%5B3%5D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%20%7D%20%7D%20%7D%7D)
Answer:
did u ever find out the answer ?
Step-by-step explanation:
Answer:
y=6
y=3
y=-3
y=-5
x=3
x=5
x=-1
x=-4
Step-by-step explanation:
The percentage here must be assumed as by volume. Therefore, it means that the solution has 0.18 gallons of detergent / gallon of solution. If Meryl needs to add 11 gallons of water then she has 2.41 gallons of detergent. Calculation is as follows:
.18 = x / x+4
Solving for x, we obtain
x = 2.41
Answer:
<h2><u>$ 0.30</u></h2>
Step-by-step explanation:
5 ÷ 1.50 = 0.30
therefore the unit price of an ounce of Pringles if 5 ounces cost $ 1.50 is <em><u>$</u></em><em><u>0</u></em><em><u>.</u></em><em><u>3</u></em><em><u>0</u></em>