The probability that a two-digit number selected at random has a tens digit less than its units digit is 0.2667 (4/15).

There are 90 two-digit numbers (99-9). Of these, six numbers are divisible by 15 (15, 30, 45, 60, 75, 90). This is also divisible by 5. Therefore, the preferred case is 30-6 = 24. Therefore, the required probability is 24/90 = 4/15.
The probability of an event can be calculated by simply dividing the number of favorable results by the total number of possible results using a probabilistic expression. Whenever you are uncertain about the outcome of an event, you can talk about the probability of a particular outcome, that is, its potential.
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Answer:
hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23
Step-by-step explanation:
Lets plug in the answer choices and see which one works
A. x = -6
| -6 | < 3
6 < 3
False, so A is not the answer
B. x = -5
| -5 | < 3
5 < 3
False, so B isn't the answer
C. x = -1
| -1 | < 3
1 < 3
True, so C is the answer.
But lets just check D to make sure C is the answer.
D. x = 2
| 2 | < 3
2 < 3
False, so D isn't the answer either.
C is your answer :)
If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)