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DerKrebs [107]
3 years ago
5

The force of gravity on the moon is approximately one sixth that of the earth. The direct variation formula for weight on the ea

rth compared to weight on the moon would be e = 6m, where e = weight on the earth and m = weight on the moon. What would be the weight of a 180 pound man on the moon?
Mathematics
2 answers:
avanturin [10]3 years ago
7 0

To answer this specific problem, the weight of a 180 pound man on the moon is 30 lbs. I am hoping that this answer has satisfied your query about and it will be able to help you, and feel free to ask another question if you’d like.

salantis [7]3 years ago
3 0
Okay the answer is 30 because if you divide 180 by 6 then that would give you 30 pounds as his weight. :)
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One solution of x^2-64=0 is 8. what is the other solution?
ivann1987 [24]
X² - 64 = 0
(x - 8)(x + 8) = 0

x = - 8, 8

Your other solution is - 8
4 0
3 years ago
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Joe is 1.6 m tall. His shadow is 2 m long when he stands 3 m
Alla [95]

Answer:

Step-by-step explanation:

6 0
1 year ago
8775 find the prime factorization of the number
OLEGan [10]

8775

/     \

3     2925

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3      975

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5 0
3 years ago
How can i calculate the growth rate of the values below
Grace [21]

Answer:

  12%

Step-by-step explanation:

The equation for the growth is ...

  f(t) = (initial value)×(growth multiplier per period)^(number of periods)

where the growth multiplier is often expressed as a percentage added to 1:

  multiplier = 1+r

  growth rate = r

__

This equation has two unknowns:

  • initial value
  • growth multiplier

In order to find these, you can make use of two of the supplied data points. I like to choose the ones that are farthest apart, as they tend to average out any errors due to rounding.

Clearly, the table tells you the initial value is 210. If you don't believe, you can put the numbers in the equation to see that:

  f(0) = (initial value)×(growth multiplier)^0

  210 = (initial value)×1

  (initial value) = 210

__

Using the last data point, we get ...

  f(7) = 210×(growth multiplier)^7

  464 = 210×(growth multiplier)^7 . . . . . . . . . fill in table value

  2.209524 = (growth multiplier)^7 . . . . . . .  divide by 210

You can solve this a couple of ways. My calculator is able to take the 7th root, so I can use it to find ...

  \sqrt[7]{2.209524}=\text{(growth multiplier)}\\1.119916\approx \text{(growth multiplier)}

Alternatively, you can use the 1/7 power:

  2.209524^(1/7) = (growth multiplier)

Another way to solve this is to use logarithms:

  log(2.209524) = 7×log(growth multiplier) . . . . . take the log

  log(2.209524)/7 = log(growth multiplier) . . . . . divide by 7

  0.04918553 ≈ log(growth multiplier)

  growth multiplier = 10^0.04918553 ≈ 1.11992 . . . . take the antilog

So, our growth multiplier is ...

  1 + r ≈ 1.11992

  r ≈ .11992 ≈ 12.0%

The rate of growth is about 12% in each period.

_____

Collapsing all of that to a single calculation:

  growth rate = (464/210)^(1/(7-0)) -1 ≈ 12.0%

8 0
3 years ago
Jan walks 40 meters in 15 secongs
mihalych1998 [28]
(I don't know what your question is, but if you're asking about the rate, I got it.)

Answer: 2.6666... meters per second

Explanation/Calculation:
Divide 40 by 15 to get the rate. You get 2 2/3 meters or 2.6666... meters per second.

Hope this helps! :)
7 0
3 years ago
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