A study is performed in a large southern town to determine whether the average weekly grocery bill per four-person family in the

Question

3 years ago

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A study is performed in a large southern town to determine whether the average weekly grocery bill per four-person family in the

town is significantly different from the national average. The national average grocery bill is $100 (standard deviation unknown). A random sample of 25 families is taken in the town, and the mean is found to be 103.23 with a standard deviation of 8.82.
For each item below, please show your work and/or explain your reasoning to receive full credit.
a). State the null and alternative hypotheses for this situation.
b). Assuming a 0.05 level of significance, compute the appropriate test statistic.
c). Find the critical t value. Can you reject the null hypothesis? Explain/justify your response using numbers and words

Mathematics

2 answers:

OLga [1] · Answer 1 · 2022-06-21T13:25:59+03:00

Answer:

The average weekly grocery bill per four-person family in the town is significantly different from the national average.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100

Sample mean, $\bar{x}$ = $103.23

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = $8.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 100\text{ dollars}\\H_A: \mu \neq 100\text{ dollars}$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{103.23- 100}{\frac{8.82}{\sqrt{25}} } = 1.831$

Now,

$t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = \pm 2.063$

Since,

$t_{stat} < t_{critical}$

We accept the null hypothesis.

We accept the null hypothesis and determine that the average weekly grocery bill per four-person family in the town is significantly same to the national average.