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Vaselesa [24]
4 years ago
9

78 square ft, height is 6ft what is the base

Mathematics
1 answer:
aniked [119]4 years ago
3 0
If the height is 6ft then the base is 13ft.

78/6=13

Hope this helps. 
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Consider the surface defined by the equation x3 + y3 + z3 = 3xyz. Use implicit differ- ∂z entiation to find ∂x. (Note z is not a
Aloiza [94]

Answer:    

   \frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

Step-by-step explanation:

Given equation is x^{3}+y^{3}+z^{3}=3xyz ………………(1)

we use derivative formula \frac{d}{dx}(x^{n})  = n x^{n-1}

\frac{d}{dx}(x^{3)}  = 3 x^{2}

\frac{d}{dx}(z^{3)}  = 3 z^{2}

And also apply 'u v' formula

\frac{d}{dx}(uv})  = u\frac{d}{dx}(v)+v\frac{d}{dx}(u)

Differentiating  equation (1) partially with respective to 'x' , we treated 'y' as constant.

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =3y(x\frac{∂z}{∂x}+z(1))   ( here y treated as constant so the derivative of constant function is zero in addition but in multiplication the constant is keep as like 'y').

on simplification , we get

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =(3yx\frac{∂z}{∂x}+3yz)

again simplification, we get

3z^{2}\frac{∂z}{∂x}- 3yx\frac{∂z}{∂x}=3yz-3x^{2}

taking common '\frac{∂z}{∂x} on left on side , we get

(3z^{2}- 3yx)\frac{∂z}{∂x}=3yz-3x^{2}

dividing '(3z^{2}- 3yx) on both sides, we get

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

<u>Final answer</u>:-

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

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3 years ago
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Answer:

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The number of mosquitoes at the beach has increased by 50% every year since 2012. In 2012, there were 2,500 mosquitoes. How many
xxTIMURxx [149]

Answer:

Step-by-step explanation:

2012 = 2500

2500 x .50 = 1250

2500 + 1250

2013 = 3750

3750 x .50 =

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5625 + 2812.5

2015= 8437.5

8437.5 x .50 = 4218.75

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2016= 12656.25

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2017= 18984.375

18984.375 x .50 = 9492.1875

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2018= 28,476.5625‬

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3 years ago
-1/2x&gt;-2x - (-3/4x +1)
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The acute angle of the right angle triangle are in the ratio of 4:5​
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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