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DIA [1.3K]
3 years ago
5

The number of mosquitoes at the beach has increased by 50% every year since 2012. In 2012, there were 2,500 mosquitoes. How many

mosquitos were there in 2018?
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

Step-by-step explanation:

2012 = 2500

2500 x .50 = 1250

2500 + 1250

2013 = 3750

3750 x .50 =

3750 + 1875

2014 = 5625

5625 x .50 = 2812.5

5625 + 2812.5

2015= 8437.5

8437.5 x .50 = 4218.75

8437.5 + 4218.75

2016= 12656.25

12656.25 x .50 = 6328.125

12656.25 + 6328.125

2017= 18984.375

18984.375 x .50 = 9492.1875

18984.375 + 9492.1875

2018= 28,476.5625‬

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Evgesh-ka [11]
17 - 6 x 10 ÷ 2 + 12 = 17 - 60 ÷ 2 + 12 = 17 - 30 + 12 = -13 + 12 = -1
7 0
3 years ago
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5(4+3√24-5(8+9÷3)³<br>ayuds​
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Step-by-step explanation:

6 0
3 years ago
The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.
galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439    

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}

a) P(No high level of contamination)

We put x = 0, in the formula.

P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0
3 years ago
If b2 + 2b − 24 = 0, and b &lt; 0, what is the value of b?
Effectus [21]

Answer: b = -6, 4

Step-by-step explanation:

Convert into factored form :

(b+6)(b-4)

Then make one of the terms 0.

3 0
3 years ago
Weiming receives a weekly pocket money of $28. If he decides to save 20% of it, find his saving in a year and spendings in a yea
Maru [420]

Welming's spending is $1164.8 and his savings is $291.2

<h3>How to determine the savings and the spending?</h3>

The given parameters are:

Weekly pocket = $28

Save = 20%

There are 52 weeks in a year.

So, the yearly pocket is:

Yearly pocket = $28 * 52

Evaluate

Yearly pocket = $1456

He saves 20%.

So, we have:

Savings = 20% * $1456

Evaluate

Savings = $291.2

His spending is then calculated as:

Spending = $1456 - $291.2

Evaluate

Spending = $1164.8

Hence, Welming's spending is $1164.8 and his savings is $291.2

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7 0
2 years ago
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