The formula that is useful for solving both of these problems is ...
9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
Answer:
A) 2
Step-by-step explanation:
Start off with the given information. The question states that the x-int. is 4, so you should recognize that there is a point at (4,0). Plug the point into the equation.
k(4) + 2(0) + 8 = 0
Now simplify the equation.
4k + 0 + 8 = 0
Isolate the variable, make sure it's on its own side.
4k = 8
Now get the k by itself to solve the equation. Divide both sides by 4.
k = 2
Answer:
P(X > 10), n = 15, p = 0.7
P(X > 10) =P(10 < X ≤ 15) = P(11 ≤ X ≤ 15) = P(X = 11, 12, 13, 14, 15)
=P(X = 11) + P(X =12) + P(X = 13) + P(X =14) + P(X = 15) (because these are disjoint events)
Step-by-step explanation:
See attached image for detailed explanation
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