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Anna007 [38]
3 years ago
7

Which postulate can be used to prove that △ABD≅△CBD?

Mathematics
2 answers:
lawyer [7]3 years ago
4 0
I believe AAS can be used to prove that △ABD≅△CBD?
lidiya [134]3 years ago
3 0
Side angle side (SAS) theorem
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Solve for x in this equation:3/4+|5-x|=13/4
S_A_V [24]
Well, anything in absolute value lines become positive, so the equation would be:

3/4+5+x=13/4

Next we subtract 3/4 to both sides to start separating the variable (x).

So, 5+x=10/4


Next, we subtract 5 from both sides. (5= 20/4)

And we get: x=-10/4.

I hope this helps!
7 0
3 years ago
Read 2 more answers
Tay–Sachs Disease Tay–Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carri
BARSIC [14]

Answer:

a) 0.0156 = 1.56% probability that all children will develop the disease.

b) 0.4219 = 42.19% probability that only one child will develop the disease.

c) 0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they carry the disease, or they do not. The probability of a children carrying the disease is independent of any other children, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that their offspring will develop the disease is approximately .25.

This means that p = 0.25

Three children:

This means that n = 3

Question a:

This is P(X = 3). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.25)^{3}.(0.75)^{0} = 0.0156

0.0156 = 1.56% probability that all children will develop the disease.

Question b:

This is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.25)^{1}.(0.75)^{2} = 0.4219

0.4219 = 42.19% probability that only one child will develop the disease.

c. The third child will develop Tay–Sachs disease, given that the first two did not.

Third independent of the first two, so just multiply the probabilities.

First two do not develop, each with 0.75 probability.

Third develops, which 0.25 probability. So

p = 0.75*0.75*0.25 = 0.1406

0.1406 = 14.06% probability that the third children will develop the disease, given that the first two did not.

6 0
3 years ago
Nathan has 80 us stamps,64 Canadian stamps,and 32 Mexican stamps. He wants to put the same number of stamps on each page. Each p
Feliz [49]

Answer:

The greatest number of stamps that Nathan can put on each page = 16.

Step-by-step explanation:

Given:

Nathan has:

80 US stamps

64 Canadian stamps

32 Mexican stamps

The stamps need to put on a page such that each page has same number of same country stamps on each page.

To find the greatest number of stamps he can put on each page.

Solution:

In order to find the greatest number of stamps Nathan can put on each page, we will find the G.C.F. of the three numbers.

The numbers are:

80,64,32

<em>We will list down the prime factors of each number.</em>

80=2\times 2\times 2\times 2\times 5

64=2\times 2\times 2\times 2\times 2\times 2

32=2\times 2\times2\times 2\times 2

The G.C.F can be given as = 2\times 2\times 2\times 2 = 16

Thus, the greatest number of stamps that Nathan can put on each page = 16.

6 0
3 years ago
If you can buy 1/3 of a box of chocolates for 6 dollars how much can you purchase for 4 dollars?
sladkih [1.3K]

You  \: can \: purchase :4 \times  \frac{1}{3}  \div 6 =  \frac{2}{9}  \: of \: a \: box

5 0
3 years ago
The cost of renting a kayak for one hour is $23. Each additional hour is $8 more. Write the formulas to represent the situation.
sergiy2304 [10]

Answer:

Step-by-step explanation:

Add and then multiply the one left

6 0
3 years ago
Read 2 more answers
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