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2 years ago

50% of 25,000 =fifty percent of twenty five thousand equal

Mathematics

2 answers:

Over [174]2 years ago

5 0

50% = 1/2

so 25,000 / 2 = 12,500

charle [14.2K]2 years ago

5 0

The correct answer is 12,500.

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Please help me with this!!!

guajiro [1.7K]

Answer: 41

Step-by-step explanation:

9*(-2)*(-2) - 4*(-2) - 3 = 9*4 + 8 - 3 = 36 + 5 = 41

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3 years ago

The expanded fom of (a-b)²

emmainna [20.7K]

Answer:

Step-by-step explanation:

$(a-b)^{2}$ = $a^{2}$ - 2ab + $b^{2}$

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3 years ago

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64 = 4(p + 2) + 24 please solve step by step

Wittaler [7]

Answer:

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16

Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .

-16 + 1 = -15

-8 + 2 = -6

-4 + 4 = 0

-2 + 8 = 6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8

p2 - 2p + 8p - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

p • (p-2)

Add up the last 2 terms, pulling out common factors :

8 • (p-2)

Step-5 : Add up the four terms of step 4 :

(p+8) • (p-2)

Which is the desired factorization

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2 years ago

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PLEASE SOMEONE GOOD AT MATH HELP IM HAVING A MENTAL BREAKDOWN

Alenkinab [10]

Find the hight and the base that might help

5 0

2 years ago

A detective finds a victim of murder at 9 am. At that time, the temperature of the body is 90.3 degrees F. One hour later, the b

LekaFEV [45]

Answer:

Step-by-step explanation:

Given

at 9 am temperature of the body is $90.3^{\circ}F$

1 hr later temperature $89^{\circ}F$

Temperature of room $T=68^{\circ}F$

According to newtons law

$\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-T_{room}\right )$

$\frac{\mathrm{d} T}{\mathrm{d} t}=-k\left ( T-68\right )$

$\frac{dT}{T-68}=-kdt$

Integrating

$=\int \frac{dT}{T-68}=-kdt$

$\ln |T-68|=-kt+c$

$T-68=Ae^{-kt}$

Now at 9 am i.e. t=0,

$90.3=A+68$

$A=22.3$

At 10 am i.e. t=1 hr T=89

$89-68=22.3e^{-k}$

$e^{-k}=21$

$k=0.06006$

Temperature of Normal human body is $T=98.6 ^{\circ}F$

$98.6-68=e^{-0.06006t}$

$30.6=e^{-0.06006t}$

Taking log both sides

$t=-5.27$

i.e. 5 hr and 16.2 min

i.e. victim murdered at 3 am and 43.8 min

7 0

2 years ago