Let p: The shape is a rhombus. Let q: The diagonals are perpendicular. Let r: The sides are congruent. Which represents "The sha pe is a rhombus if and only if the diagonals are perpendicular and the sides are congruent”?
1 answer:
Given that <span>p represents
"The shape is a rhombus", q represents "The diagonals are perpendicular", and r represents
"The sides are congruent". "if and only if" is represented using the biconditional logic operator (↔) and "and" is represented using the logical conjuction operator (∧). Therefore, "The shape is a rhombus if and
only if the diagonals are perpendicular and the sides are congruent” is represented by "p ↔ (q ∧ r)" </span>
You might be interested in
Answer:
Step-by-step explanation:
y = x² + 4x is an up-opening parabola with x-intercepts 0 and -4.
y ≥ 0 when x≤-4 or x≥0
range: (-∞,-4)∪[0,+∞)
If u add up 15,17, and 19 they add up to 51
Hi there!
Work out the parenthesis.
Combine like terms.
Subtract 9 from both sides.
Subtract 4x from both sides
Divide both sides by -9
That's not a squre anyway, we use ratios base:person to corner=28:8 height to height=x:5 so 28/8=x/5 becasue same ratio 28/8=14/4=7/2 7/2=x/5 multiply 35/10=2x/10 35=2x divide 2 17.5=x x=17.5 feet