All categories

3 years ago

The value of y varies directly as x, with a constant of variation of -8. What is the value of y when x is 7?

Mathematics

2 answers:

slega [8]3 years ago

6 0

Answer:

y = -56

Step-by-step explanation:

The equation for direct variation is

y = kx where k is the constant of variation

y = -8 x

We know x =7

y = -8*7

y = -56

denis-greek [22]3 years ago

6 0

Answer:

-56

Step-by-step explanation:

y = kx,

Where k = -8

y = -8x

y = -8(7)

y = -56

You might be interested in

Use long division to find the quotient and remainder. {4x^4-5x^2+5x+9}/{x+1}

Vlada [557]

Answer:

quotient: 4x^3 -4x^2 -x +6

remainder: 3

Step-by-step explanation:

See the attached for the long division. As with any long division, at each step, the quotient term multiplies the divisor and the result is subtracted to form the new dividend.

5 0

2 years ago

Determine if the numbers are parallel, perpendicular or netiher.

Margarita [4]

Answer:

Parallel :)

Step-by-step explanation:

thats the tea sis.

4 0

3 years ago

Please help!! What is the measure of angle 1?

melomori [17]

Answer:

120 i think

Step-by-step explanation:

4 0

2 years ago

Direction: Choose the letter of the best answer and we

VARVARA [1.3K]

Answer:

Step-by-step explanation:

To find (g ￮ f)(x), substitute x = f(x) into g(x) , that is

g(2x - 5)

= 3(2x - 5) + 4

= 6x - 15 + 4

= 6x - 11 → C

5 0

2 years ago

. An individual wishes to invest $5000 over the next year in two types of investment: Investment A yields 5%, and investment B y

tresset_1 [31]

Answer:

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

Step-by-step explanation:

Let

x -----> the amount invested at Investment A yields 5%

y -----> the amount invested at Investment B yields 8%

we know that

$x+y=5,000$

$x=5,000-y$ -----> equation A

$x \geq 0.25(5,000)$

$x \geq \$1,250$ -----> inequality B

$y \leq 0.50(5,000)$

$y \leq \$2,250$ -----> inequality C

$x \geq \frac{1}{2}y$ -----> inequality D

Substitute equation A in the inequality D and solve for y

$5,000-y \geq \frac{1}{2}y$

Multiply by 2 both sides

$10,000-2y \geq y$

Multiply by -1 both sides

$-10,000+2y \leq -y$

Adds y both sides

$-10,000+2y+y \leq 0$

$-10,000+3y \leq 0$

adds 10,000 both sides

$3y \leq 10,000$

Divide by 3 both sides

$y \leq \$3,333.33$ -----> inequality E

therefore

Solve for y

we have

$y \leq \$2,250$ -----> inequality C

$y \leq \$3,333.33$ -----> inequality E

The solution of inequality C and inequality E is

$y \leq \$2,250$

For y=2,250

x=5,000-y ----> x=5,000-2,250=2,750

$x \geq \$2,750$ -----> inequality F

Solve for x

we have

$x \geq \$1,250$ -----> inequality B

$x \geq \$2,750$ -----> inequality F

The solution of inequality B and inequality F is

$x \geq \$2,750$

therefore

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

7 0

2 years ago