All categories

3 years ago

The value of y varies directly as x, with a constant of variation of -8. What is the value of y when x is 7?

Mathematics

2 answers:

slega [8]3 years ago

6 0

Answer:

y = -56

Step-by-step explanation:

The equation for direct variation is

y = kx where k is the constant of variation

y = -8 x

We know x =7

y = -8*7

y = -56

denis-greek [22]3 years ago

6 0

Answer:

-56

Step-by-step explanation:

y = kx,

Where k = -8

y = -8x

y = -8(7)

y = -56

You might be interested in

2369 divided by 6= t

kvasek [131]

The answer to this is 394.83.

8 0

2 years ago

Read 2 more answers

I need help ASAP! <:

fomenos

Answer:

the answer is 15 square units

8 0

3 years ago

Read 2 more answers

Please help me! This is a full assignment I’m struggling on haha! Please answer each question and I’ll give Brainliest to whoeve

Marina86 [1]

Answer:

Step-by-step explanation:

3 0

2 years ago

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

4 0

3 years ago

6. Evaluate /(x) = -4x - 5 for x = -1.

Stels [109]

Answer:

-1

Step-by-step explanation:

-4(-1)-5=4-5=-1

3 0

2 years ago