IA triangular parking lot is paved outside a new shopping center. The lengths of the sides of the parking lot are 100 meters, 11
1 answer:
Answer:
Step-by-step explanation:
I believe the only way to solve this is by Heron's Formula.
Add up all the sides and divide by 2 to get the semi-perimeter:
113+100+86 = 299
299/2 = 149.5
Now fill in the rest, which looks like this:
where s is your semiperimeter value, a is the length of one side, b the length of another side, and c the length of the third side:
which simplifies to
which simplifies further to
which, on your calculator, is 4141.49 meters squared (that's rounded to the nearest hundredth).
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The question is incomplete. The map is attached as a photo and here is the complete question:
a. What is the actual distance between Saugerties and
Kingston? ___________________________
b. Catskill is 15 miles from Saugerties. What would the
distance on the map be? ___________________________
c. On another map, the distance between Saugerties and
Kingston is 2 inches. What would the distance from Saugerties to
Catskill be on this map? __________________
Since you have asked the answer for part (c) only, here is the answer:
Answer:
<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>
Step-by-step explanation:
On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>
To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:
1 inch ---------- 2.5 miles
4 inches ------ x miles
Cross multiplying:
1x = 2.5 x 4
x = 10 miles
The actual distance between Saugerties and Kingston is 10 miles.
On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles
The scale on the other map is 1 inch = 5 miles.
Catskill is 15 miles from Saugerties (given in the previous part). So on the map:
1 inch -------- 5 miles
y inch ------- 15 miles
Cross multiplying:
15 = 5y
y = 15/5
<u>y = 3 inches.</u>
The distance from Saugerties to Catskill would be 3 inches on this map.
