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Pepsi [2]
2 years ago
9

1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the

given equation. (2,-2);y=-x-2 A.y=-2x B.y=2x C.y=1/2x D.y=-x 2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6 A.y=-3/2x+1 B.y=-3/2x-1 C.y=-3/2x+2 D.y=-3/2x+4 3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3 A.y=2 B.y=2x+4 C.y=4x D.y=4 4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1 A.y=1/2x+1 B.y=-2x-1 C.y=1/2x-1 D.y=-1/2x-1 5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3) A.y=-1/2x+5 B.y=2x-5 C.y=1/2x-2 D.y=-1/2x+5/2
Mathematics
2 answers:
Colt1911 [192]2 years ago
8 0

Answer:

It’s 5/2

Step-by-step explanation:

Kryger [21]2 years ago
5 0
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2

D.y=-x

2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6

C.y=-3/2x+2  

3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
 D.y=4

4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1

B.y=-2x-1 

5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)

 D.y=-1/2x+5/2</span>
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