6. Solve for x in the figure below.
1 answer:
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Answer:
Among the given options, the one which can be used as a minimum qualifying score to join the volleyball league is, 274.
Step-by-step explanation:
Let the team tryout scorecard is represented by the random variable X.
Now, according to the question,
X Normal (250 , 15)
Let Z = -----------------------(1)
So, Z Normal (0, 1)
According to the question, the bottom 95% in the tryout scorecard are to be eliminated.
Let, P(Z ≤ ) = 0.95
Now, from the inverse standard normal probability table,
= 1.645
So, if we say that
P(X ≤ ) = 0.95, then
--------------[from (1)]
=
= 274. 675
Hence, from the given options, the answer is, 274.
Very interesting problem
