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Yuki888 [10]
2 years ago
13

The standard form of an absolute value function is fx) -ax-h1+k. Which of the following represents the vertex?

Mathematics
1 answer:
disa [49]2 years ago
6 0

Answer:

(h

Step-by-step explanation:

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Determine the 20th term of the sequence: -14,-8, -2, 4, 10,
Pie

Answer: The 20th term is 100

Step-by-step explanation: It adds by 6 each time

-14, -8, -2, 4, 10, 16, 22, 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88, 94, 100

3 0
2 years ago
HELP!! Triangle A′B′C′ is the image of triangle ABC after a dilation.
Nina [5.8K]
Down three and over left four so something like (-3, -4) im pretty sure
3 0
3 years ago
Which multiplication expression is eqeul to 3/5 ÷ 1/2
eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

1 \frac{1}{5}

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

1 \frac{1}{5}

So option a = 3/5 x 2/1 is ur answer

8 0
2 years ago
Read 2 more answers
Graph the function.<br> y = -6x2 - 12x -1
artcher [175]
Answer:

Step by step explanation
7 0
2 years ago
Please help with the questions in the image
iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have -2x^3 + 5x^2 + 9

m = slope = derivative

Find the derivative / slope of -2x^3 + 5x^2 + 9

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

\frac{d}{dx}(-2x^3 + 5x^2 + 9)

-6x^2 + 10x

m = -6x^2 + 10x when x = a

<em>Now that we have this information, we can answer question b</em>

<u>Question b</u>

<u>The tangent line for Point (1, 12)</u>

First find the slope by using our derivative.

m = -6x^2 + 10x

m = -6(1)^2 + 10(1)

m = -6 + 10x

m = 4

Now that we have our slope, use point slope form to find our tangent line

y - 12 = 4(x - 1)

y(x) = 4x + 8


<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

m = -6x^2 + 10x

m = -6(2)^2 + 10(2)

m = -24 + 10

m = -4

Now find the tangent line using point slope form of a line.

y(x) - 13 = -4(x - 2)

y(x) = -4x + 21


Now graph the lines, which I have done and you can see by viewing the image I have attached.


6 0
3 years ago
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