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3 years ago

If B is the midpoint of AC and the length of AC is 23.8 what is the legength of AB

1 answer:

swat323 years ago

4 0

Hey there,

So explain and to illustrate (how $B$ is the midpoint of $AC$ and the length of $AC$ is 23.8 what is the length of $AB$

<span> A-----------------B----------------C
</span>
So, $\boxed{AC}$ in the problem here is to be considered the (Whole area of this line). $AC$ is the whole thing.

So, what we do in this problem, we do . . .

23.8 ÷ 2 because we need to find what is $AB$ , so we will find the one half of it, which in this illustration is to be considered $AB$

23.8 ÷ 2 = $\boxed{11.9}$

$\boxed{AB=11.9}$

Hope this helps.
~Jurgen

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The sum of a number and 3 is equal to 5 less than double that number. What is the number?

Ganezh [65]

Answer:

sum of a number 2 plus3 is equal to 5

and less than its double 2×2=4 so the answer is 2

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3 years ago

Read 2 more answers

At noon, the minute and the hour hands of a clock overlap. In how long will they again overlap?

kati45 [8]

Answer:

Okay. At noon, the hour and minute hand overlap. First, let’s calculate the speed of the hands.

The minute hand rotates once around the clock every hour. It goes 360 degrees in 60 minutes, so it rotates 360/60 or 6 degrees per minute. The hour hand goes once around the clock every 12 hours. Because there are 60 minutes in an hour, it goes 360 degrees 12*60 or 720 minutes. This means it travels at a speed of 360/720 or 0.5 degrees per minute.

Once the clock starts, the minute hand goes ahead and rotates ahead of the hour hand. At 1:00, the minute hand is at 12, and the hour hand is ahead at 1. This is where we will start our calculations.

Now, we have a variable, m, which is the minutes that have passed since the clock started. So, our minute hand speed is 6m, and our hour hand speed is 0.5m. However, because the hour hand is at one, it is at 30 degrees. (360/12 * 1.) This means our equation is 6m = 0.5m+30.

Now, we calculate.

6m = 0.5m+30

5.5m = 30

m = 30/5.5

m = 5.45

So at 5.45 minutes, the minute hand is at the hour hand. However, because one hour has passed since we started, we have to add on one hour.

So, our final total is 1 hour 5 minutes and 27 seconds.

Step-by-step explanation:

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3 years ago

Shannon's chair is 20 inches tall. How tall is it in centimeters?

JulsSmile [24]

Answer:

50.8 centimeters

Step-by-step explanation:

So, if Shannon's chair is 20 inches tall, you would multiply that by 2.54 in order to get the length in centimeters.

20 x 2.54 = 50.8.

So Shannon's char is 50.8 centimeters tall.

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3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

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3 years ago

0.000309 in scientific notation

trasher [3.6K]

Hey there :)

Writing in scientific notation means a should be
0 ≤ a < 10

Therefore, 0.000309 will be written as
3.09 x 10ⁿ

3 is the 4th decimal place value

so n = - 4

3.04 x 10⁻⁴

3 0

3 years ago