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solmaris [256]
3 years ago
11

Round 52961 to one significant figure

Mathematics
1 answer:
Aneli [31]3 years ago
7 0

Answer: 50000

Step-by-step explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.

All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.

All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

Thus 52961 when rounded off to one significant figure will be 50000.

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Read 2 more answers
Write a recursive rule and an explicit rule for the<br> sequence<br> 3,7,11,15
m_a_m_a [10]

Answer:

The Recursive formula for the sequence is:

aₙ = aₙ₋₁ + d

The Explicit formula for the sequence is:

a_n=4n-1

Step-by-step explanation:

Given the sequence

3,7,11,15

Here:

a₁ = 3

computing the differences of all the adjacent terms

7 - 3 = 4, 11 - 7 = 4, 15 - 11 = 4

The difference between all the adjacent terms is the same and equal to

d = 4

We know that a recursive formula basically defines each term of a sequence using the previous term(s).

The recursive formula of the Arithmetic sequence always involves the first term.

a₁ = 3

We know that, in the Arithmetic sequence, every next term can be obtained by adding the common difference and the preceding term.

so

The recursive formula of the sequence is:

aₙ = aₙ₋₁ + d

substitute n = 2 to find the 2nd term

a₂ = a₂₋₁ + d

a₂ = a₁+ d

substitute a₁ = 3 and d = 4

a₂ = 3 + 4

a₂ = 7

Thus, the recursive formula for the sequence 3,7,11,15 is:

aₙ = aₙ₋₁ + d

<u>An explicit rule for the sequence</u>

Given the sequence

3,7,11,15

We already know that

a₁ = 3

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

substituting a₁ = 3 and d = 4

a_n=4\left(n-1\right)+3

a_n=4n-4+3

a_n=4n-1

Therefore, an explicit rule for the  sequence

a_n=4n-1

6 0
2 years ago
Which expressions are equivalent to (5g+3h+4)\cdot2(5g+3h+4)⋅2left parenthesis, 5, g, plus, 3, h, plus, 4, right parenthesis, do
hichkok12 [17]

Answer:

C  None of the above

Step-by-step explanation:

Here are the required options

Choose all answers that apply

A  (5g+3h).8  

B  (5g+3h).6  

C  None of the above

Given the expression;

(5g+3h+4).2

Expand

(5g+3h+4).2

= 2(5g+3h+4)

= 2(5g) + 2(3h) + 2(4)

= 10g+6h+8

Checking option A;

(5g+3h).8

Expand

= 8(5g+3h)

= 8(5g) + 8(3h)

= 40g+24h

Checking option B:

(5g+3h).6

Expand

= 6(5g+3h)

Using the distributive law;

= 6(5g) + 6(3h)

= 30g+18h

Since none of the expressions for A and B is equivalent to 10g+6h+8, hence <u>NONE of the options are correct</u>

6 0
2 years ago
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