Since the area of the circle is only 3.14. that means 3.14 out of one hundred units can be hit. so you have a 3.14% chance of hitting the circle in the middle. SO the probability is very close to 0.
100 - 3.14 = 96.86, so we have a 97 percent chance (approximately) of landing in the white space, This is very close to one.
Answer:
Third option is correct. Scale factor 3 ; enlargement.
Step-by-step explanation:
It is given that the figure A'B'C'D' is a dilation of figure ABCD.
We know that after dilation the corresponding sides of image and preimage are in the same proportion.
The image of AD is A'D'.
From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).
Distance formula is



Scale factor is constant which represents the relation between image and preimage.



Therefore the scale factor is 3.
If k>0 it means enlargement and if k<0 it means reduction. Therefore third option is correct.
Using the normal distribution, it is found that 1851 people would have an IQ less than 115.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of IQ scores less than 115 is the <u>p-value of Z when X = 115</u>, hence:


Z = 1
Z = 1 has a p-value of 0.8413.
Out of 2200 people:
0.8413 x 2200 = 1851.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
17/50
Step-by-step explanation:
34% = 34/100 --> 34/100 * 1 = 34/100 * (1/2)/(1/2) = (34/2) / (100/2) = 17/50