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Gwar [14]
3 years ago
12

Shalondra was late making her monthly car payment last month and had to pay a late fee. Her car payment was $325.00 and she was

charged a 4% late fee. How much did she have to pay in all last month?
Mathematics
2 answers:
xz_007 [3.2K]3 years ago
4 0
$338.00 is what she had to pay in all
KengaRu [80]3 years ago
3 0

Answer:

the answer is 130

Step-by-step explanation:

325.00 x .4

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What is 3 over 4 times 7
cupoosta [38]

Answer:

21/4

Step-by-step explanation:

3/4 x 7

you need to multiply 7 by the 3 which gives you 21

so 21/4

8 0
3 years ago
First change to standard form of first order linear differential equation and then by finding the appropriate integrating factor
Leokris [45]

Answer:

Step-by-step explanation:

Given is a Differential equation as

xy' + y = lnx ; y(e)=1

To bring it to linear form we can divide the full equation by x

y'+\frac{y}{x} =\frac{ln x}{x}

This is of the form

y'+p(x) *y = q(x)

p(x) = 1/x

So find

e^{\int\limits{\frac{1}{x} } \, dx } = e^{ln x} = x

Solution is

xy = \int  {x*lnx /x } \, dx =xln x -x +C

Use the initial value as y(e) =1

e= eln e -e+C\\C=e

So solution is

xy =xln x -x+e

5 0
3 years ago
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
andriy [413]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

(c) Standard deviation of defective light bulbs = 3.67

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

Standard deviation of defective light bulbs is given by = S.D. = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.67

8 0
3 years ago
Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8
garri49 [273]

Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

8 0
3 years ago
how do the graphs of f(x) = sin x and g(x) = sin2x+3 compare. Must make two selections of the following that apply.
Elena L [17]

Answer:

The correct options are:

  • g(x) is shifted three units higher than f(x).
  • g(x) has a period that is half the period of  f(x).

Step-by-step explanation:

We have to compare the graphs of the function:

f(x)=\sin x

and g(x)=\sin 2x+3

We have to select the correct options among the following:

As we know that the period of sine function is 2π.

i.e. Period of function f(x) is: 2π.

The period of sin(2 x) is π.

Hence, the period of the function g(x) function is π.

  • Hence, the period of g(x) is half the period of f(x).
  • Also we could observe that g(x) is shifted 3 units upward.

3 0
3 years ago
Read 2 more answers
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