Answer:
65.3658 inches
Step-by-step explanation:
Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value 
such that 
, but, 
, i.e., 
is the 76th percentile of the standard normal distribution. So, 
, 
. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
Dilation is scale factor, like a dilation scale factor of 2
There are 16 (3/8s) in 6.
Answer:
To answer items such as this, we directly substitute the a + 2 to the all the x's in the function such that,
f(a + 2) = (3 + a + 2) / (a + 2 - 3)
Simplifying the function generated above,
f(a + 2) = (5 + a) / (a - 1)
