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2 years ago

Please

Mathematics

1 answer:

igomit [66]2 years ago

5 0

x=1/4y+2

−4x+3y=4-------> substitution method

-4(1/4y+2)+3y=4

-y-8+3y=4- --------> 2y=4+8- ----->y=6

x=1/4y+2- -----> ¼(6)+2=7/2

the answer is (7/2,6)

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Choose the correct correspondence RT

Marizza181 [45]

$RT$ corresponds to TR. correct option b.

Step-by-step explanation:

In the given parallelogram or rectangle , we have a diagonal RT . We need to find which side is in correspondence with side/Diagonal RT of parallelogram URST .

Side TU:

In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side TU with RT.

Side TR:

Since, direction of sides are not mentioned here , we can say that TR & RT is parallel & equal to each other . So , TR is in correspondence with side/Diagonal RT of parallelogram URST .

Side UR:

In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side UR with RT.

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3 years ago

Y=6(x-7)^2……. any one know this ?

alex41 [277]

Answer: 6x^2-84x+294

Step-by-step explanation:

Use the foil method to solve (x-7)^2 and then multiply your result by 6.

4 0

2 years ago

Read 2 more answers

Graham and Hunter are circus performers. A cable lifts Graham into the air at a constant speed of 1.5 ft/s. When Graham’s arms a

lidiya [134]

Answer: Hello there!

this type of equations in one dimension (when all the factors are constants) are written as:

h = initial position + initial velocity*t + (acceleration/2)*t^2

First, let's describe the hunter's equation:

We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.

If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:

h = 18 + 1.5t

where t in seconds.

Now, the equation for the ball:

We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)

the equation for the ball is:

h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2

So the system is:

h = 18 + 1.5t

h = 5 +24t - 16.1t^2

so the right answer is A

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3 years ago

What is the difference x + 5/ x + 2 - x + 1 /x^2 + 2x

xxTIMURxx [149]

2x^3 + 2x^2 + 5x + 1/ x^2

3 0